The intensity of the light has no connection with the photoelectric effect.
That's what was so baffling about it before the particle nature of light
was suspected ... a match with a blue flame might stimulate the
photoelectric effect, but a high-power red searchlight couldn't do it.
<h2>Question:</h2>
Appliances connected so that they form a single pathway for charges to flow are connected in a(n)
<h2>Answer:</h2>
<u>A</u><u>.</u><u> </u><u>Series</u><u> </u><u>circuit</u><u> </u>
<h2>
<u>#CARRYONLEARNING</u><u> </u></h2><h2>
<u>#STUDYWELL</u><u> </u></h2>
Things are rubbed against each other
Answer:=14,160 kJ
Explanation: Let m1 and m2 be the initial and final amounts of mass within the tank, respectively. The steam properties are listed in the table below
Specific Internal SpecificTemp Pressure Volume Energy Enthalpy Quality Phase
C MPa m^3/kg kJ/kg kJ/kg
1 260 4.689 0.02993 2158 2298 0.7 Liquid Vapor Mixture
2 260 4.689 0.0422 2599 2797 1 Saturated Vapor
The mass initially contained in the tank is m1 = V/v1
m1 =0.85 m^3 /0.02993 m^3 /kg
= 28.4 kg
The mass finally contained in the tank is
m2 =V2/v
= 0.85 m^3 /0.0422 m^3 /kg
= 20.14 kg
The heat transfer is then
Qcv = m2u2 − m1u1 − he(m2 − m1)
Qcv = (20.14)(2599) − (28.4)(2158) − (2797)(20.14 − 28.4) = 14,160 kJ
Answer:
0.34 s
Explanation:
Given that,
Initial speed of a ball, u = 5.8 m/s
It is kicked at an angle of 17.0° above the horizontal.
The vertical component of velocity will be,

Let it takes t time in the air before it lands on the ground again. It can calculated as :

So, it will take 0.34 seconds.