Answer:
Explanation:
Magnetic field near current carrying wire
= 
i is current , r is distance from wire
B = 10⁻⁷ x 
force on second wire per unit length
B I L , I is current in second wire , L is length of wire
= 10⁻⁷ x x 33 x 1
= 3234 x 
This should balance weight of second wire per unit length
3234 x = .075
r = 
x 10⁻⁷
= .0043 m
= .43 cm .
Answer:
The mass of 0.02 m³ of gold is 386 kilograms
Explanation:
Given:
The density of the gold = 19300 kg/m³.
The volume of gold = 0.02 m³
To Find:
The mass of gold = ?
Solution:
We know that density is mass divided per unit volume.
Thus mathematically
Density = \frac{mass}{volume}Density=
volume
mass
Rewriting in terms of mass ,
Mass = density * volume
On substituting the known values
Mass = 19300 kg/m³ * 0.02 m³
Mass = 386 kilograms
Learn more about Mass and Density:
Mass=?,volume=190,density=4
Mass 350 kg volume 175 density ans
This is not my answer I copied it but hope it helps:)
Explanation:
The object is moving along the parabola y = x² and is at the point (√2, 2). Because the object is changing directions, it has a centripetal acceleration towards the center of the circle of curvature.
First, we need to find the radius of curvature. This is given by the equation:
R = [1 + (y')²]^(³/₂) / |y"|
y' = 2x and y" = 2:
R = [1 + (2x)²]^(³/₂) / |2|
R = (1 + 4x²)^(³/₂) / 2
At x = √2:
R = (1 + 4(√2)²)^(³/₂) / 2
R = (9)^(³/₂) / 2
R = 27 / 2
R = 13.5
So the centripetal force is:
F = m v² / r
F = m (5)² / 13.5
F = 1.85 m
1. Traveling by car means you have specific roads to follow. You won’t be able to go straight to Banning high from POLAHS. The 8.4km will be defined as distance. Traveling by helicopter you don’t have roads to follow that means you can fly directly to banning high. 6.8km will be defined as displacement.
2. A) 400m
B)0m
C)d=1/2(vi+vf)t
400=1/2(0+vf)92
8.7m/s
D) 0m/s
E) Not sure but instantaneous velocity refer to velocity at a given point. Average velocity is just the average. Usually instantaneous velocity won’t be same as the average velocity.
Plz like if it helped.
Answer:
Kinetic energy = (1/2) (mass) (speed²)
Original KE = (1/2) (1430 kg) (7.5 m/s)² = 40,218.75 joules
Final KE = (1/2) (1430 kg) (11.0 m/s)² = 86,515 joules
Work done during the acceleration = (40218.75 - 86515) = 46,296.25 joules
Power = work/time = 46,296.25 joules / 9.3 sec = 4,978.1 watts .
Explanation:
Dont report my answer please
