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Alexus [3.1K]
2 years ago
15

HELPPPPPP!!!! Jupiter has a gravity that is 2.4 times that of Earth. A person has a mass of 60kg. What is the mass of this perso

n on Jupiter?
60 kg

144 kg

600N

1440N

​
Physics
1 answer:
mafiozo [28]2 years ago
3 0

60

because mass of an object never change

but weight can change for example if it's

mass is 60kg 5he wieght will be 60kg * 9.8m/s²

=588N

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The magnetic field on the Sun is created by______.
Ber [7]
The answer is actually c hope this helps
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8 0
3 years ago
Why are the eggs and confectioner’s sugar amounts easy to work with to make 8 brownies?
Orlov [11]

Answer:

Because they are both easy to measure (?)

Explanation:

(I'm not really sure, there are no choices. If there were different options I might be able to better answer this)

6 0
3 years ago
Estimate how long the sun would last if it were merely a huge fire that was releasing chemical energy. Assume that the sun begin
stepan [7]

Answer:

≅ 17000 years or 1.7 x 10⁴ years

Explanation:

time= total energy/power

=  (10⁸J/kg)(2x10³⁰ kg) / 3.8 x 10²⁶ J/s

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=  16689 years

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7 0
3 years ago
If two micro coulomb of charge is flowing in a circuit for 5 minutes. What is the amount of current in the circuit?
Murrr4er [49]

Answer:

6.67×10¯⁹ A

Explanation:

From the question given above, the following data were obtained:

Quantity of electricity (Q) = 2 μC

Time (t) = 5 mins

Current (I) =?

Next, we shall convert 2 μC to C. This can be obtained as follow:

1 μC = 1×10¯⁶ C

Therefore,

2 μC = 2 μC × 1×10¯⁶ C / 1 μC

2 μC = 2×10¯⁶ C

Next, we shall convert 5 mins to seconds. This can be obtained as follow:

1 min = 60 secs

Therefore,

5 min = 5 min × 60 sec / 1 min

5 mins = 300 s

Finally, we shall determine the current in the circuit. This can be obtained as follow:

Quantity of electricity (Q) = 2×10¯⁶ C

Time (t) = 300 s

Current (I) =?

Q = It

2×10¯⁶ = I × 300

Divide both side by 300

I = 2×10¯⁶ / 300

I = 6.67×10¯⁹ A

Thus, the current in the circuit is 6.67×10¯⁹ A

4 0
2 years ago
When a flat slab of transparent material is placed under water, the critical angle for light traveling from the slab into water
Novosadov [1.4K]

Answer:

(a) 40.6 degree

Explanation:

When refraction takes place from slab to water, the critical angle is 60 degree.

Use Snell's law

refractive index of water with respect to slab

\mu _{w}^{s}=\frac{Sin60}{Sin90}

\frac{\mu _{w}}{\mu _{s}}=0.866

\frac{1.33}{\mu _{s}}=0.866

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Now for slab air interface, the critical angle is C.

\mu _{a}^{s}=\frac{SinC}{Sin90}

\frac{\mu _{a}}{\mu _{s}}=\frac{SinC}{Sin90}

1 / 1.536 = Sin C

C = 40.6 degree

3 0
3 years ago
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