Answer:
Fs = 32N
Fh = 21 N
Explanation:
Statics
Let Fs be the force of the shoulder, assumed upward
Let Fh be the force of the hand, assumed downward
Sum moments about the hand to zero
1.1(9.8)[67] - Fs[22.5] = 0
Fs = 32N
Sum vertical forces to zero
32 - Fh - 1.1(9.8) = 0
Fh = 21 N
Or we could sum moments about the shoulder point
1.1(9.8)[67 - 22.5] - Fh[22.5] = 0
Fh = 21 N
Or, G = [M1 L1 T-2] × [L]2 × [M]-2 = [M-1 L3 T-2]. Therefore, the gravitational constant is dimensionally represented as M-1 L3 T-2.
Answer:
10.53m/s²
Explanation:
Centripetal acceleration is the acceleration of an object about a circle. The formula for calculating centripetal acceleration is expressed by:
v is the velocity of the car = 24.5m/s
r is the radius of the track = 57.0m
Substitute the given values into the formula:
Hence the centripetal acceleration of the race car is 10.53m/s²
Answer:
Newton's third law of motion.
Explanation:
Every action has an equal and opposite reaction.
Answer:
0.303s
Explanation:
horizontal distance travel = 2.050 m, vertical distance travel = 0.45 m
Using equation of linear motion
Sy = Uy t + 1/2 gt² Uy is the inital vertical component of the velocity, t is the time taken for the vertical motion in seconds, and S is the vertical distance traveled, taken downward vertical motion as negative
-0.45 = 0 - 0.5 × 9.81×t²
0.45 / (0.5 × 9.81) = t²
t = √0.0917 = 0.303 s
