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2 years ago

15

HELPPPPPP!!!! Jupiter has a gravity that is 2.4 times that of Earth. A person has a mass of 60kg. What is the mass of this perso

n on Jupiter?
60 kg

144 kg

600N

1440N

1 answer:

mafiozo [28]2 years ago

3 0

60

because mass of an object never change

but weight can change for example if it's

mass is 60kg 5he wieght will be 60kg * 9.8m/s²

=588N

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Vector A has a magnitude of 30 units. Vector B is perpendicular to vector Aand has a magnitude of 40 units. What would the magni

Fudgin [204]

Answer:

$|\vec A + \vec B| = 50 units$

Explanation:

As we know that magnitude of two vectors is given as

$|\vec A + \vec B| = \sqrt{A^2 + B^2 + 2AB cos\theta}$

here we know that

A = magnitude of vector A

B = magnitude of vector B

$\theta$ = angle between two vectors

so here we know that

A = 30 units

B = 40 units

angle = 90 degree

so we have

$|\vec A + \vec B| = \sqrt{30^2 + 40^2 + 2(30)(40)cos90}$

$|\vec A + \vec B| = \sqrt{30^2 + 40^2}$

$|\vec A + \vec B| = 50 units$

3 0

2 years ago

n ultraviolet light beam having a wavelength of 130 nm is incident on a molybdenum surface with a work function of 4.2 eV. How f

pashok25 [27]

Answer:

The speed of the electron is 1.371 x 10⁶ m/s.

Explanation:

Given;

wavelength of the ultraviolet light beam, λ = 130 nm = 130 x 10⁻⁹ m

the work function of the molybdenum surface, W₀ = 4.2 eV = 6.728 x 10⁻¹⁹ J

The energy of the incident light is given by;

E = hf

where;

h is Planck's constant = 6.626 x 10⁻³⁴ J/s

f = c / λ

$E = \frac{hc}{\lambda} \\\\E = \frac{6.626*10^{-34} *3*10^{8}}{130*10^{-9}} \\\\E = 15.291*10^{-19} \ J$

Photo electric effect equation is given by;

E = W₀ + K.E

Where;

K.E is the kinetic energy of the emitted electron

K.E = E - W₀

K.E = 15.291 x 10⁻¹⁹ J - 6.728 x 10⁻¹⁹ J

K.E = 8.563 x 10⁻¹⁹ J

Kinetic energy of the emitted electron is given by;

K.E = ¹/₂mv²

where;

m is mass of the electron = 9.11 x 10⁻³¹ kg

v is the speed of the electron

$v = \sqrt{\frac{2K.E}{m} } \\\\v = \sqrt{\frac{2*8.563*10^{-19}}{9.11*10^{-31}}}\\\\v = 1.371 *10^{6} \ m/s$

Therefore, the speed of the electron is 1.371 x 10⁶ m/s.

8 0

3 years ago

What is a appropriately?????

telo118 [61]

Answer:

In a way that is suitable or right for a particular situation or occasion: She didn't think we were appropriately dressed for a wedding. Business leaders who acted appropriately were widely praised. See. appropriate.

5 0

2 years ago

A 3.04 kg particle is located on the x-axis at xm = −8 m, and a 5.61 kg particle is on the x-axis at xM = 3.56 m. Find the coord

Murljashka [212]

Answer:

center of mass = −0.50 m

Explanation:

given data

mass m1 = 3.04 kg

distance xm = -8 m

mass m2 = 5.61 kg

distance xM = 3.56 m

solution

we get here center of mass for n mass of system that is express as

center of mass = $\frac{m_1x_1+m_2x_2......m_nx_n}{m_1+m_2...m_n}$ ......................1

but we have only 2 particle system so we will get

center of mass = $\frac{m1 \times xm+m2 \times xM}{m1+m2}$ .................2

put here value and we will get

center of mass = $\frac{3.04 \times (-8 )+5.61 \times 3.56}{3.04 + 5.61}$

solve it we will get

center of mass = −0.50 m

8 0

3 years ago

Light travels at the speed of approximately 3.0 × 108 meters per second. Find the time in minutes required for light to travel f

Solnce55 [7]

Answer:

t = 8.33 minutes

Explanation:

given,

Speed of Light, v = 3 x 10⁸ m/s

distance between sun to Earth = 1.5 x 10¹¹ m

time taken to reach earth = ?

we know,

Distance = speed x time

$t = \dfrac{d}{s}$

$t = \dfrac{1.5\times 10^{11}}{3\times 10^8}$

t = 500 s

1 min = 60 s

now, $t = \dfrac{500}{60}\ minutes$

t = 8.33 minutes

time taken by the light to reach earth is equal to 8.33 minutes.

3 0

3 years ago