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Valentin [98]
3 years ago
13

A youngster throws a rock from a bridge into the river 50 m below. The rock has a speed of 15 m/s when it leaves the youngster’s

hand. Calculate the velocity of the rock when it strikes the water if it is thrown upward.
...?
Physics
1 answer:
butalik [34]3 years ago
6 0
Assuming that the stone is thrown vertically... let's say it's a 1 kg stone.It doesn't matter if it's thrown upwards or downwards as (assuming no air friction) it will pass the original throwing point with the same downwards velocity as it had upwards, 3 seconds previously. So it starts with 1/2 m v^2 = 0.5 * 1 * 15^2 = 112.5 J of keThen k.e. gained = gpe lostk.e. gained = m g h = 1 * 10 * 50 = 500 J of Ke gainedso the final (total) ke is 612.5 J which = 1/2 m v^2 = 0.5 v^2 here
so 0.5 v^2 = 612.5so     v^2    = 1225so v = 35 m/s
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If you increase speed you have to increase force to keep a balance Newton's second law.
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3 years ago
Explain why changing the axis of rotation of an object changes its moment of inertia.
Yuri [45]

The mass distribution along a particular axis affects the moment of inertia.

<h3>What is the moment of inertia?</h3>

Each component of the object's mass is now located at a different distance from the axis than it was previously if the axis is altered. Axes perpendicular to the rod that first travel through its center of mass and then through one of its ends are used to compare the moments of inertia of uniformly stiff rods.

As an illustration, you can easily change the direction of rotation by repeatedly wriggling a meter stick along an axis that passes through its center of mass. You will have a harder time moving the stick back and forth if you shift the axis to the end. Because a major portion of the stick's mass is located farther from the axis, the moment of inertia around the end is much larger.

To learn more about moment of inertia, refer to:

brainly.com/question/14460640

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7 0
2 years ago
A solid sphere of radius R is made of a metallic conductor. A hollow spherical shell of the same radius R is made of the same co
Harrizon [31]

1-2) They have same surface charge density

3-4) The metallic conductor has greatest surface charge density

Explanation:

1-2)

In a conductor, the charge carriers (mainly electrons) are free to move. Therefore, as a result, they tend to move at the largest possible distance from each other, because of the repulsive force that they exert on each other.

The configuration that maximize the distance between the charge carriers for a solid sphere of metallic conductor is the one in which all the electrons are on the surface, and they are equally spaced between each other. This means that for the solid sphere of radius R, the excess charge Q will be entirely spread over the surface of the sphere.

Similarly, the excess charge Q on the hollow spherical shell (which is also made of the same conducting material) will also be spread over the surface with the charge carriers at the maximum distance from each other. Therefore, the surface charge density for both objects will be

\sigma = \frac{Q}{4\pi R^2}

where R is the radius of the two spheres.

3-4)

In this case, the surface charge density on the two objects is different.

In fact, on the metallic sphere (conducting) the surface charge density is (as explained in part 1):

\sigma = \frac{Q}{4\pi R^2}

Hoever, the second sphere is made of an insulating material. In an insulator, the charge carriers are not free to move. If the initial charge Q is spread across the all sphere (which is not hollow), this means that some of the charge will actually also be inside the sphere. So the charge deposited on the surface, Q', will be less than the total charge Q. Therefore, the surface charge density will be

\sigma' = \frac{Q'}{4\pi R^2}

And since Q' < Q, this means that \sigma', so the conducting sphere has a greatest surface charge  density.

4 0
3 years ago
Find the net force for <br> 10 N<br> 10 N<br> 25degree<br> 5N<br> 5N
icang [17]

Answer:

30n

Explanation:

7 0
3 years ago
how many bits are required to sample an incoming signal 4000 times per second using 64 different amplitude level
Gelneren [198K]

Answer:

6 bits

Explanation:

The quality of digitized signal can be improved by reducing quantizing error. This is done by increasing the number of amplitude levels, thereby minimizing the difference between the levels and hence producing a smoother signal.

Also, Sampling frequently (also known as oversampling) can help in improving signal quality.

To get the number of bits, we use:

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Given an amplitude level of 64, hence:

2ⁿ = 64

2ⁿ = 2⁶

n = 6 bits

6 0
3 years ago
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