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Yakvenalex [24]

3 years ago

5

How are the terms difference, sum,quotient and product alike?

2 answers:

Eva8 [605]3 years ago

7 0

<u> </u> <span><span> More than is the symbol > also called greater than meaning that if x > y then x is more than y.

Sum is + and is the result after addition.

Quotient is the result after dividing.

Product is the result after multiplying.</span>
</span>

oksano4ka [1.4K]3 years ago

3 0

Theyre all answers to problems
Sum = answer to addition problem
Difference = answer to subtraction problem
Product = answer to multiplication problem
Quotient = answer to division problem

You might be interested in

Using principle of mathematical induction prove that 6^-1 divisble by 5 .

salantis [7]

I suppose the claim is $5 \mid 6^n - 1$ for $n\in\Bbb N$ .

When $n=1$ , we have $6^1 - 1 = 6 - 1 = 5$ , and of course 5 divides 5.

Assume the claim holds for $n=k$ , that $5 \mid 6^k - 1$ . We want to use this to show it holds for $n=k+1$ , that $5 \mid 6^{k+1} - 1$ .

We have

$6^{k+1} - 1 = \left(6^{k+1} - 6\right) + \left(6 - 1) = 6\left(6^k - 1\right) + 5$

Since $5 \mid 6^k - 1$ , we can write $6^k - 1 = 5\ell$ for some integer $\ell$ . Then

$6^{k+1} - 1 = 6\cdot5\ell + 5 = 5(6\ell + 1)$

which is clearly divisible by 5. QED

5 0

1 year ago

The height of each story of an apartment building is measured from the bottom of one floor to the next floor.

eduard

If each story is 18 feet and there are 30 stories.. the building is 550 feet tall

you would do:
$18 \times 30 = 550$

3 0

3 years ago

Can someone help me with these two questions I’m 10 points

GalinKa [24]

(1) answer for this question is 6/51 to 1

(2)the answer for this question is (d)58.50

4 0

3 years ago

Need help with this question

posledela

Answer:

QR = 82.38 to nearest hundredth.

Step-by-step explanation:

As they are similar corresponding sides are in the same ratio.

So MN / QR = LM / QR

13/51 = 21/ QR

`3QR = 51*21

QR = 51*21/13

QR = 82.38

4 0

3 years ago

A metallurgist has one alloy containing 34% copper another containing 48% copper. How many pounds of each alloy must he use to m

Zielflug [23.3K]

Answer:

<h2>36.14 pounds of 34% copper alloy and 9.86 pounds of 48% copper alloy</h2>

Step-by-step explanation:

First alloy contains 34% copper and the second alloy contains 48% alloy.

We wish to make 46 pounds of a third alloy containing 37% copper.

Let the weight of first alloy used be $x$ in pounds and the weight of second alloy used be $y$ in pounds.

Total weight = $46\text{ }pounds=x+y$ $-(i)$

Total weight of copper = $37\%\text{ of 46 pounds = }34\%\text{ of }x\text{ pounds + }48\%\text{ of }y\text{ pounds }$

$\dfrac{37\times 46}{100}=\dfrac{34x}{100}+\dfrac{48y}{100}\\\\ 34x+48y=1702$ $-(ii)$

Subtracting 34 times first equation from second equation,

$34x+48y-34x-34y=1702-34\times46\\14y=138\\y=9.857\text{ }pounds \\x=36.143\text{ }pounds$

∴ 36.14 pounds of first alloy and 9.86 pounds of second alloy were used.

5 0

3 years ago