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Natali [406]
3 years ago
10

Dr. Laude doesn’t care for fancy definitions of a mole. He prefers the idea that a mole is:

Chemistry
1 answer:
seropon [69]3 years ago
8 0

Answer:

A

Explanation:

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One useful tool that may help a scientist interpret data by revealing unexpected patterns is a
Andrew [12]
Graph would be the answer.

I hope this helps. :)
7 0
4 years ago
Iodine-131 is administered orally in the form of NaI(aq) as a treatment for thyroid cancer. The half-life of iodine-131 is 8.04
evablogger [386]

Answer:

16.6 mg

Explanation:

Step 1: Calculate the rate constant (k) for Iodine-131 decay

We know the half-life is t1/2 = 8.04 day. We can calculate the rate constant using the following expression.

k = ln2 / t1/2 = ln2 / 8.04 day = 0.0862 day⁻¹

Step 2: Calculate the mass of iodine after 8.52 days

Iodine-131 decays following first-order kinetics. Given the initial mass (I₀ = 34.7 mg) and the time elapsed (t = 8.52 day), we can calculate the mass of iodine-131 using the following expression.

ln I = ln I₀ - k × t

ln I = ln 34.7 - 0.0862 day⁻¹ × 8.52 day

I = 16.6 mg

8 0
3 years ago
In the Bohr model of the atom, the electrons move in fixed, ________ paths around a dense, positively-charged nucleus. On the ot
trapecia [35]
Answer:

Answers are in parentheses.

In the Bohr model of the atom, the electrons move in fixed, (circular) paths around a dense positively-charged nucleus. On the other hand, the quantum mechanical model shows the probability of finding an electron as a (cloud) of negative charge.
6 0
3 years ago
Read the description of how ancient metalworkers improved their iron. Then identify the solute and solvent by filling in the bla
slega [8]

Answer:iron and carbon

Explanation:I took the test it’s iron and carbon

6 0
4 years ago
Read 2 more answers
Use bond energies to calculate δhrxn for the reaction. n2(g)+3cl2(g)→2ncl3(g)
Jobisdone [24]
ΔHrxn = ΣδΗ(bond breaking) - ΣδΗ(bond making)

Bond enthalpies,
N ≡ N ⇒ 945 kJ mol⁻¹
N - Cl ⇒ 192 kJ mol⁻¹
Cl - Cl⇒ 242 kJ mol⁻¹

According to the balanced equation,
ΣδΗ(bond breaking)  = N ≡ N x 1 + Cl - Cl x 3
                                  = 945 + 3(242)
                                  = 1671 kJ mol⁻¹
ΣδΗ(bond making)    = N - Cl x 3 x 2
                                 = 192 x 6
                                 = 1152 kJ mol⁻¹

δHrxn = ΣδΗ(bond breaking) - ΣδΗ(bond making)
          = 1671 kJ mol⁻¹ - 1152 kJ mol⁻¹
          = 519 kJ mol⁻¹
3 0
4 years ago
Read 2 more answers
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