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pogonyaev
2 years ago
9

Given that E

Chemistry
1 answer:
bija089 [108]2 years ago
5 0

The equilibrium constant of the reaction is 1.21 * 10^6 while the change in free energy is -34.7 kJ.

<h3>What is equilirium constant?</h3>

The equilibrium constant shows the extent of conversion of reactants to products.

Now we know from the Nernst equation that;

Ecell = E°cell - 0.0592/n logQ

E°cell = 0.52−0.16=0.36 V

Since Ecell = 0 V at equilibrium,

0 = 0.36 - 0.0592/1 log K

0.36  = 0.0592/1 log K

log K = 0.36/ 0.0592

K = antiog (0.36/ 0.0592)

K = 1.21 * 10^6

ΔG = -RT lnK

ΔG =-(8.314 * 298 * ln1.21 * 10^6)

ΔG =-34.7 kJ

Learn more about equilibrium constant:brainly.com/question/10038290

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Put the following metric units in order from largest to smallest pL, mL, dL, kL
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Answer:

kL, dL, mL, pL

Explanation:

pL stands for picoliters. This is equal to 1 × 10⁻¹² (0.000000000001) liters.

mL stands for milliliters. This is equal to 1 × 10⁻³ (0.001) liters.

dL stands for deciliters. This is equal to 1 × 10⁻¹ (0.1) liters.

kL stands for kiloliters. This is equal to 1 × 10³ (1000) liters.

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How many moles are in 255 mL of a 2.35 M solution of H2SO4?
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When solutions of sodium sulfide and copper(ii) sulfate are mixed, a precipitate of copper(ii) sulfide is formed. what is the ne
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When solutions of sodium sulfide and copper(ii) sulfate are mixed, a precipitate of copper(ii) sulfide is formed. The net ionic equation for this reaction is Cu⁺² (aq) + S⁻² (aq) → CuS (s).

<h3>What is Balanced Chemical Equation ?</h3>

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

Now first write the balanced chemical equation

CuSO₄ (aq) + Na₂S (aq)  → CuS(s) + Na₂SO₄ (aq)

Now write the net ionic equation

Cu⁺² (aq) + SO₄⁻² (aq) + 2Na⁺ (aq) + S⁻² (aq) → CuS (s) + 2Na⁺ + SO₄⁻² (aq)

So the net ionic equation is

Cu⁺² (aq) + S⁻² (aq) → CuS (s)

Thus from the above conclusion we can say that When solutions of sodium sulfide and copper(ii) sulfate are mixed, a precipitate of copper(ii) sulfide is formed. The net ionic equation for this reaction is Cu⁺² (aq) + S⁻² (aq) → CuS (s).

Learn more about the Balanced Chemical Equation here: brainly.com/question/26694427

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