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1 year ago

Given that E

1 answer:

5 0

The equilibrium constant of the reaction is 1.21 * 10^6 while the change in free energy is -34.7 kJ.

<h3>What is equilirium constant?</h3>

The equilibrium constant shows the extent of conversion of reactants to products.

Now we know from the Nernst equation that;

Ecell = E°cell - 0.0592/n logQ

E°cell = 0.52−0.16=0.36 V

Since Ecell = 0 V at equilibrium,

0 = 0.36 - 0.0592/1 log K

0.36 = 0.0592/1 log K

log K = 0.36/ 0.0592

K = antiog (0.36/ 0.0592)

K = 1.21 * 10^6

ΔG = -RT lnK

ΔG =-(8.314 * 298 * ln1.21 * 10^6)

ΔG =-34.7 kJ

Learn more about equilibrium constant:brainly.com/question/10038290

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Which of the following elements is the least reactive metal? Sodium, Rubidium, Chlorine, and Magnesium.

LuckyWell [14K]

First off chlorine is not a metal so you can ignore that one.

Sodium and Rubidium are in group 1 of the periodic table and Magnesium is in group 2.

Group one metals are more reactive than group two because it is harder for the group two metals to lose their 2 valence (outer most) electrons.

As you go down group 1 there is an increase in the reactivity this is because as you go down there is an increase in the atomic radius which leads to more shielding. This weakens the electrostatic forces of attraction making it easier to lose the outermost electrons, therefore they are more reactive.

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2 years ago

How many molecules are in 13 moles of oxygen?

natima [27]

Answer:

mass/13of molecules .........

8 0

3 years ago

Read 2 more answers

A radioisotope decays to give an alpha particle andPb-208.

oee [108]

<u>Answer:</u> The original element is $_{84}^{212}\textrm{Po}$

<u>Explanation:</u>

Alpha decay is defined as the process in which alpha particle is emitted. In this process, a heavier nuclei decays into a lighter nuclei. The alpha particle released carries a charge of +2 units.

The released alpha particle is also known as helium nucleus.

$_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_2^4\alpha$

For the given alpha decay process of an isotope:

$^{Z}_{A}\textrm{X}\rightarrow ^{208}_{82}\textrm{Pb}+_2^4\alpha$

<u>To calculate A:</u>

Total mass on reactant side = total mass on product side

A = 208 + 4

A = 212

<u>To calculate Z:</u>

Total atomic number on reactant side = total atomic number on product side

Z = 82 + 2

Z = 84

The isotopic symbol of unknown element is $_{84}^{212}\textrm{Po}$

Hence, the original element is $_{84}^{212}\textrm{Po}$

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3 years ago

How many moles of c2h6o are in a 24.5 gram sample?

andreev551 [17]

0.5326086957 moles ....

5 0

3 years ago

What volume of 12.0 M sulfuric acid is needed to prepare 300.0 mL of 2.50 M solution?

Zepler [3.9K]

Answer:

n=c*V

=2.50*300x10^-3

=.75 moles of hcl

v=n/c

=.75/12

=.0625 L

convert to mL

=62.5mL

4 0

3 years ago