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pogonyaev
1 year ago
9

Given that E

Chemistry
1 answer:
bija089 [108]1 year ago
5 0

The equilibrium constant of the reaction is 1.21 * 10^6 while the change in free energy is -34.7 kJ.

<h3>What is equilirium constant?</h3>

The equilibrium constant shows the extent of conversion of reactants to products.

Now we know from the Nernst equation that;

Ecell = E°cell - 0.0592/n logQ

E°cell = 0.52−0.16=0.36 V

Since Ecell = 0 V at equilibrium,

0 = 0.36 - 0.0592/1 log K

0.36  = 0.0592/1 log K

log K = 0.36/ 0.0592

K = antiog (0.36/ 0.0592)

K = 1.21 * 10^6

ΔG = -RT lnK

ΔG =-(8.314 * 298 * ln1.21 * 10^6)

ΔG =-34.7 kJ

Learn more about equilibrium constant:brainly.com/question/10038290

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