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Tema [17]
3 years ago
15

How are monosaccharides and polysaccharides structurally different? *NO PLAGIARISM PLS*

Chemistry
2 answers:
Brut [27]3 years ago
8 0
  • C personalities are organized and controlled. They take their time completing tasks accurately, like to research things thoroughly, and are always prepared.  Because they put so much time and effort into everything they do, they hate to be criticized. They are perfectionists at heart and take even the smallest complaint personally.  This makes them extremely difficult to confront. The best way to approach it is to focus on parts of the problem largely out of the C personality’s control or aspects of the problem they might not have considered.  Make it clear that you appreciate all of their efforts and that you’re bringing something to their attention because it’s a variable that they need to have in the equation in the future. No matter what, don’t frame the conflict as a personal attack. If you do, the C personality will likely become resentful and go out of their way to avoid future interactions with you.!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!<u>!</u><u>!</u><u>!</u><u>!</u><u>!</u><u>!</u><u>!</u><u>!</u><u>!</u><u>!</u>
Mariana [72]3 years ago
3 0

Explanation:

Monosaccharides are simple carbohydrates that cannot be further hydrolyzed to simpler carbohydrates. They contain between three and six carbon atoms per molecule.

Polysaccharides  are complex carbohydrates . They are condensation polymers derived from very long chains of monosaccharide units.

Structurally, polysaccharides are made up of repeating units of monosaccharides.

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Describe the number and type of each component of the molecule methane
Tasya [4]

Answer:

Methane is a chemical compound with the molecular formula CH4. It is the main component in natural gas. Methane is considered the simplest of alkanes, compounds that consist only of hydrogen (H) and carbon (C) elements. Methane is an odorless, colorless, tasteless gas that is lighter than air.

Explanation:

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3 years ago
A red blood cell placed in saline solution will shrink.<br> True or false? Explain please?
Scorpion4ik [409]
Yes a red blood cell placed in a sline solution shrinks because of the process of osmosis.
5 0
3 years ago
Is kingdom more specific taxon than family?
Eva8 [605]
Yes the kingdom is more specific
5 0
3 years ago
A geochemist in the field takes a 46.0 mL sample of water from a rock pool lined with crystals of a certain mineral compound X.
inysia [295]

Answer:

The solubility of the mineral compound X in the water sample is 0.0189 g/mL.

Explanation:

Step 1: Given data

The volume of water sample = 46.0 mL.

The weight of the mineral compound X after evaporation, drying, and washing = 0.87 g.

Step 2: Calculate the solubility of X in water

46.00 mL of water sample contains 0.87 g of the mineral compound X.

To calulate how many grams of the mineral compound  1.0 mL  of water sample contains:

0.87 g/46.0 mL = 0.0189 g.

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3 0
3 years ago
Determine the equilibrium constant for the acid-base reaction between ethanol and hydrobromic acid? Acid pKa Hydrobromic Acid −5
siniylev [52]

Answer:

10^{-3.4

Explanation:

Let us first take a look at the image below;

In the acid - base  reaction; we can see the transfer of electrons that takes place;

We can also see that the reaction goes in the direction which converts the stronger acid and the stronger base to the weaker acid and the weaker base.

The stronger acid is shown with the one with more negative P_{Ka} Value.

∴ The equilibrium constant for the acid-base reaction is expressed as:

K_{eq}= \frac{K_a of reactant acid}{K_a of product acid}

      = \frac{10^{-pK} of reactant acid}{10^{-pk} of product acid}

From  P_{Ka} Value (shown in the image below), it is clear and vivid that hydrobromic acid is a stronger acid than the ethyloxonium ion, therefore the equilibrium lies to the right.

From the chemical equation (shown in the attached image); the equilibrium constant for the acid-base reaction can be expressed as:

K_{eq}=\frac{10^{-pK} of hydrobromic acid}{10^{-pk} of Ethyloxonium acid}

K_{eq}=\frac{10^{-5.8} of hydrobromic acid}{10^{-2.4} of Ethyloxonium acid}

       = 10^{-3.4}

6 0
3 years ago
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