-3x - 4y - 2z = 0
x + 3y + 2z = 1
-2x - y = 1
-4x - 4y - 2z = 10
3x + 4y +2z= 0
-x = 10. x = -10
-2(-10) - y = 1
20 - y = 1
-y = -19
y = 19
-10 + 3(19) + 2z = 1
-10 + 57 + 2z = 1
47 + 2z = 1
2z = -46
z= -23
check: 2(-10)+2(19)-23=-5
-20+38-23=-5
-43+38=-5
-5=-5
12 ×4^4/4^2
=12×4^2
=12×16
=192
1/8 of a quart would equal 1/4 of a pound
Hope this helps :)
Answer:
(a) 0
(b) f(x) = g(x)
(c) See below.
Step-by-step explanation:
Given rational function:

<u>Part (a)</u>
Factor the <u>numerator</u> and <u>denominator</u> of the given rational function:

Substitute x = -1 to find the limit:

Therefore:

<u>Part (b)</u>
From part (a), we can see that the simplified function f(x) is the same as the given function g(x). Therefore, f(x) = g(x).
<u>Part (c)</u>
As x = 1 is approached from the right side of 1, the numerator of the function is positive and approaches 2 whilst the denominator of the function is positive and gets smaller and smaller (approaching zero). Therefore, the quotient approaches infinity.

Endpoint T would be at the coordinates (4, -11)