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Romashka [77]
3 years ago
15

What is the measure of angle x? Enter your answer in the box. m∠x= °

Mathematics
2 answers:
devlian [24]3 years ago
4 0
Since all the angles inside a triangle add to 180°, we can write the equation:
53+44+x=180

Then you solve for x

97+x=180 (combine like terms)
x=83°

Hope this helps!
Llana [10]3 years ago
3 0
The value of x is 83.
This is because all three angles of a triangle must sum up to 180 degrees. So 53+44=97 and 180-97=83.
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Which ordered pair is a solution of the inequality? 3y-6<12x
BartSMP [9]
The answer is 3. (4, -2)
7 0
4 years ago
I NEED HELP PLEASE ! :(
denis-greek [22]

Answer:

4

Step-by-step explanation

because 256 is root of  4 raised to 4

so 4 root 4 is to 4 which is = to 4

hope it helped u i am new on brainly so counldnt write properly

if it helped u plzzz mark as brainliest

3 0
3 years ago
How many cm more than 2 m is the perimeter of a regular hexagon of side 35 cm?
bearhunter [10]
A Hexagon Is A 6 Sided Figure. So First, We Need To Know How Many Centimeters Are In A Meter. There Are 100 Centimeters In A Meter. Next, Do 2 Meters * 100 centimeters To Get 2 Meters Is Equal To 200 Centimeters. Next, We Do 35*6. We Get 210. Now, Do The Subtraction. 210-200 = 10cm. The Regular Hexagon's Perimeter Is 10cm Larger. I Hope I Helped! :D
3 0
3 years ago
A rectangular field is 95 meters long and 65 meters wide. Give the length and width of another rectangular field that has the sa
Lena [83]

Answer:

There are a ton of answers. For instance, 1m by 159m.

Step-by-step explanation:

The formula for the area is a=l*w, where l and w are constants.

The formula for perimeter is p=2l+2w

The question wants another rectangle that has the same perimeter, but a smaller area.

The perimeter of the two fields has to be:

p=(2*95)+(2*65)\\p=190+130\\p=320

Thankfully, the question never specified how much smaller the area has to be. So let's go to the logical extreme and make it 1 meter wide. To conserve the perimeter, we'd have to add the removed 64 meters to the original 95 meters of length, resulting in a rectangle with a width of 1m and a length of 159m. This results in an area of exactly 159 m^{2}. The original rectangle had an area of 6175m^{2}. Mission accomplished!

But why stop there? Let's go even further down this rabbit hole!

Instead of 1, why don't we take it several steps further and use 0.0000001? At that point, the length would end up being  159.9999999m.

The area would be 0.00001599999999 m^{2}.

Let's go further!!

Width: 0.00000000000000000001

Length: 159.99999999999999999999

Area: 0.00000000000000000001599999999999999999999 (approximate).

One more, for old time's sake.

Width: 0.00000000000000000000000000000000000000000000000001m

Length: 159.99999999999999999999999999999999999999999999999999m

Area: 0.00000000000000000000000000000000000000000000000015999999999999999999999999999999999999999999999999999 m^{2}

At that point, there's so little area in the plot of land that you could claim it has no area!

5 0
3 years ago
Quall o numero de diagonais de um poligono com 15 lados
Romashka [77]

Answer:

90 diagonais.

Step-by-step explanation:

n(n-3)/2=15(15-3)/2=15*6=90

7 0
3 years ago
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