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KonstantinChe [14]
3 years ago
14

You make a u turn in your car, what provides the centripetal force on the car and on you

Physics
2 answers:
grin007 [14]3 years ago
8 0
Newton's first and third laws
Dahasolnce [82]3 years ago
4 0

The correct answer is the frictional force.


In fact, the centripetal force is the force that keeps the car in circular motion, and it points toward the centre of the circular trajectory. The frictional force between the tyres of the car and the road provides the centripetal force that keeps the car in the turn: in fact, without the friction (e.g. on an icy road), the car would not be able to make the turn at the same speed.

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What is da answer please i need help
jolli1 [7]

Answer:

Air and water i think

Explanation:

Cause Air =25% and water=25% so that equals 50%

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Sportsmanship means following the rules of the game and respecting the judgment of referees and officials. What is another examp
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Another example of sportsmanship is playing equally with other opponents and treated appropriately.
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Describe the relationship between input force, output force,<br>and load force.​
g100num [7]

Answer: the relationship between the input force and output force is that, Input Force represents the amount of force that you put into another object (which is considered as the load force) while Output Force represents the force that a specific object has as a result of the input force.

Explanation:

Using a lever as an example, a broom is a lever used to sweep floors, the input force is applied by one of the arm used in sweeping, while the output force is on the other edge of the broom (broom tip)

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((GIVING 40 POINTS AND BRAINLIEST TO CORRECT ANSWER!)) What is shown in the diagram?
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A cardinal (Richmondena cardinalis) of mass 4.00×10−2 kg and a baseball of mass 0.146 kg have the same kinetic energy. What is t
sp2606 [1]

Answer:

0.5232

Explanation:

the cardinal and the baseball has the same kinetic energy

\frac{1}{2} m_{c} v_{c} ^{2}  = \frac{1}{2} m_{b} v_{b} ^{2}

m_{c}v_{c}^{2} = m_{b}v_{b}^{2}

[4.0X 10^{-2} ]v_{c} ^{2} = [0.146]v_{b} ^{2}

\frac{v_{c} }{v_{b} } = \sqrt{\frac{0.146}{4.0 X 10^{-2} } }

\frac{v_{c} }{v_{b} } = 1.910

Ratio of momentum

\frac{p_{c}}{p_{b}}  = \frac{m_{c}v_{c}}{m_{b}v_{b}} = \frac{ (4.0 X 10^{-2} )(1.910v_{b} )}{0.146v_{b} }

\frac{p_{c}}{p_{b}} = \frac{4.0 X  10 ^{-2} X 1.910 }{0.146}  = 0.5232

6 0
4 years ago
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