Answer:
v = 4.67 m
Explanation:
It is given that,
Height of the object is 24.8 cm
Height of the formed image is -3.09 cm
Object distance is 37.5 cm, it is negative always
We need to find the image distance. Let v is the image distance. Magnification of an object is given by the formula as follows :
So, the image is formed at a distance of 4.67 m.
Answer:
table and graph are attached
Explanation:
a) The velocity of the ball will be ...
v(t) = v0 -at
v(t) = 19.6 -9.8t
The position of the ball will be the integral of this:
h(t) = ∫v(t)·dt = 19.6t -(1/2)(9.8t^2)
The attached table calculates the vertical position in meters for the required times.
__
b) Graphs of displacement (h(t)) and velocity (h'(t)) are shown in the attachment.
Answer:
D. Inverse square
Explanation:
According to the information you are giving me, you must be referring to Coulomb's law because the electrostatic force in proportion to the displacement of charged particles is .
As you can see, there is a reason as to why this is also referred to as Coulomb's inverse square law because the r² represents the displacement or distance relative to the position of the particles which is squared, and it is inverse because the force and the product of the distance squared is equal to the product of the two charges particles multiplied by coulomb's constant (k) which is approximately 8.9875517923×10⁹ kg⋅m³⋅s⁻²⋅C⁻².