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3 years ago

14

In Miami, the number of highway accidents increased by 20% over a four year period. How many accidents were there in 2013 if the

re were 5,120 in 2009?

2 answers:

dalvyx [7]3 years ago

5 0

5120*.2=1024
5120+1024=6144

harina [27]3 years ago

4 0

6144.
there were 6144 car accidents in 2013

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Maria earns $48 every three hours she works. How much will she earn by working 13 hours?

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Answer:

$624

Step-by-step explanation:

48 x 13

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2 years ago

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The compound probability of two events, E and F, is ; the probability of E is and of F is . In two or more complete sentences, e

lorasvet [3.4K]

Answer:

Events E and F are not independent if the probability of event E occurring is affecting the probability of event F occurring.

Step-by-step explanation:

Two events are independent when the probability of one event occurring has no connection with that of the other event.

Example, when you toss a coin and roll a six sided die, the probability of getting a head or a tail has no connection with the probability of getting any number face.A real life example will be the probability going to the mall and owning a cat at home.These two have no influence on one another.

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3 years ago

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valentinak56 [21]

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2 years ago

What is the fewest number of quarters, nickels, and pennies that can be fairly exchanged for 2 quarters, 6 nickels, and 9 pennie

adoni [48]

Answer:

Your answer is 3 quarters, 2 nickels, and 4 pennies

Step-by-step explanation:

2 quarters plus 6 nickels plus 9 pennies is equal to 89 cents. So if we subtract 75(3 quarters) we get 14 which is less than 25 therefore we must only use nickels and pennies from now on. If we take 14 and subtract 10(2 nickels) we get 4 which less than 5 leaving us only to use pennies, which one a piece so it must be 4 pennies. Hope this helps!

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3 years ago

Which of the following have the property that a(x)=a−1(x)? I. y=x II. y=1/x III.y=x^2 IV. y=x^3 A. I and II, only B. IV, only C.

valentina_108 [34]

Answer:

<em>Correct answer:</em>

<em>A. I and II</em>

<em></em>

Step-by-step explanation:

First of all, let us have a look at the steps of finding inverse of a function.

1. Replace y with x and x with y.

2. Solve for y.

3. Replace y with $f^{-1}(x)$

Given that:

$I.\ y=x \\II.\ y=\dfrac{1}x \\III.\ y=x^2 \\IV.\ y=x^3$

Now, let us find inverse of each option one by one.

I. y = x, a(x) = x

Replacing y with and x with y:

x = y

x = $a^{-1}(x)$ = $a(x)$ Hence, I is true.

II. $y =\dfrac{1}{x}$

Replacing y with and x with y:

$x =\dfrac{1}{y}$

$x=\dfrac{1}{a^{-1}(x)}$

$\Rightarrow a^{-1}(x) = \dfrac{1}{x}$

$a^{-1}(x)$ = $a(x)$ Hence, II is true.

III. $y =x^{2}$

Replacing y with and x with y:

$x =y^{2}\\\Rightarrow y = \sqrt x\\\Rightarrow a^{-1}(x) = \sqrt{x} \ne a(x)$

Hence, III is not true.

IV. $y =x^{3}$

Replacing y with and x with y:

$x =y^{3}\\\Rightarrow y = \sqrt[3] x\\\Rightarrow a^{-1}(x) = \sqrt[3]{x} \ne a(x)$

Hence, IV is not true.

<em>Correct answer:</em>

<em>A. I and II</em>

<em></em>

4 0

3 years ago