<span>Let the 2 consecutive odd integers be represented by:
"x" and "(x+2)
_________________
The product of these two consecutive odd integers is:
________________
</span>→ <span>x*(x + 2); or, write as: x(x + 2)
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The sum </span>of these two consecutive odd integers is:
<span>________________________________
</span>→ <span>x + (x + 2) = (2x + 2)
_______________________________
The product of 2 conductive integers, "</span>x(x + 2)" , is 1 less than
4 times their sum, "(2x + 2)".
<span>______________________________
</span>→ Write as: 4*(2x + 2) − 1 = x(x + 2)
<span>________________________________
Note the distributive property of multiplication:
_______________________________
</span>→ <span>a*(b + c) = ab + ac ;
________________________________
We have:
___________
</span>→ 4*(2x + 2) − 1 = x(x + 2)
<span>_____________________________
</span> → 4*(2x + 2) = (4*2x) + (4*2) = 8x + 8
<span>____________________________________
On the "right side of the equation; we have:
______________________________________
</span>→ x(x + 2) = (x*x) + (x*2) = x² + 2x
<span>_____________________________________
We can rewrite the equation:
__________________________
</span>→ 4*(2x + 2) − 1 = x(x + 2) ;
<span>___________________________
by substituting our obtained "expanded values" for:
"[</span>4*(2x + 2)]" ; and for: "[x(x + 2)]" ;
<span>______________________________________
</span>→ 4*(2x + 2) − 1 = x(x + 2) =
____________________________
→ 8x + 8 − 1 = x² + 2x ;
__________________________________
→ Simplify the "+8 − 1" on the "left-hand side" of the equation to "7"; and subtract "2x" from EACH SIDE of the equation:
<span>____________________________________
</span>→ 8x + 7 − 2x = x² + 2x − 2x ; to get:
<span>____________________________
</span> → 6x + 7 = x² ;
________________________________
→To solve for "x"; Subtract "6x" and subtract "7"; from EACH SIDE of the equation; to get an equation in "quadratic format" ; that is:
<span>_____________________________________________
ax
let x and x+2 be the consecutive odd integers.
Their product is x(x+2)
Their sum is x + x+2 or 2x+2
x(x+2)=4(2x+2)-1
Domain is odd integers</span>
21x 3 times 7 would give you 21 and then add the x
Answer:
A
Step-by-step explanation:
x and 45° are corresponding angles and are congruent , then
x = 45 → A
Answer:
w=66
Step-by-step explanation:
w-19=47
Hey There!
So what we want to do is get the variable on one side (w) and the constant on the other
so essentially what I am saying is that we have to get rid of the -19 and to do that we have to add 19
but remember whatever we do to one side we have to do to the other
-19+19 cancels out
47+19=66
therefore
w=66
Answer:
Step-by-step explanation:
<u>Given numbers:</u>
<u>Given equation:</u>
<u>Solve:</u>
Volume is 105 in³.
