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Harrizon [31]
2 years ago
15

E. 35% of 60 is what number

Mathematics
2 answers:
loris [4]2 years ago
8 0

\text{Find 35\% of 60}\\\\\text{To find this, multiply 60 by 0.35}\\\\60 \cdot0.35=21\\\\\boxed{21}

RUDIKE [14]2 years ago
4 0

Answer:

21

Step-by-step explanation:

0.35×60 =21

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Write 8 is the whole number 11 is the <br>numerator and 20 is the denominator ​
PilotLPTM [1.2K]

Answer:

Fraction: 8 \frac{11}{20}

Decimal: 8.55

Step-by-step explanation:

8 11/20 is the answer because:

1) Since 8 is the whole number, 8 wouldn't be part of the fraction

2) The numerator is the top number in the fraction, so 11 is at the top since 11 is the numerator

3) The denominator is the bottom number in the fraction, so 20 is at the top since 20 is the denominator

8.55 is the answer because:

1) Since 8 is the whole number, 8 would be in front of the decimal point

2) When you multiply the fractions, you have to multiply until you get a hundred. Therefore, 20*5 = 100 and 11*5 = 55

Hope this helps!

7 0
2 years ago
2x7+2 ?<br> What does x =
Zarrin [17]
The x is the variable so you have to find what the equation equals in order too find out what variable x is.  2 x7+2 = 16. So now x = 16
8 0
3 years ago
Find the area of the circle 11 yd
lubasha [3.4K]
11yd is the diameter and circumference is 2πr = 2π(d/2) = πd = 11π yd
4 0
3 years ago
Read 2 more answers
X-y=1 <br> PLEASE HELP IM ON A TIME LIMIT
jekas [21]

Answer:

x = 3

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Step-by-step explanation:

8 0
3 years ago
Our club has 25 members, and wishes to pick a president, secretary, and treasurer. In how many ways can we choose the officers,
Rus_ich [418]

Answer:

13800

Step-by-step explanation:

The order of the members is important (because each selected member will receive a different position), thus we then need to use the definition of permutation.

There are 25 members, of which 3 are selected.

\begin{array}{l}n=25 \\r=3\\end{array}

Evaluate the definition of a combination:

P(25,3)=\frac{25 !}{(25-3) !}=\frac{25 !}{22 !}=25 \cdot 24 \cdot 23=13800

8 0
3 years ago
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