Which word in the sentence is the appositive?

Mathematics

2 answers:

Nina [5.8K]4 years ago

3 0

An appositive renames the noun it follows.
Charlie renames cousin.

Answer: B) Charlie

o-na [289]4 years ago

3 0

The answer is B. Charlie

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Find the curvature of the parabola y=x^2 at A(1,1)

xxMikexx [17]

Answer:

Step-by-step explanation:

The curvature of the curve y=f(x) is

$y=f(x)=x^2\\\\y'=f'(x)=2x\\\\y''=f''(x)=2\\\\K(x)=courbure(in\ French)=\Bigg|\dfrac{y''(x)}{(1+y'(x)^2)^{\dfrac{3}{2} } }\Bigg|\\\\At\ A=(1,1),\\K(1)=\Bigg|\dfrac{2}{(1+2^2)^{\dfrac{3}{2} } }\Bigg|\\\\=\Bigg|\dfrac{2}{(5)^{\dfrac{3}{2} } }\Bigg|\\\\=\Bigg|\dfrac{2}{5*\sqrt{5} }\Bigg|\\\\=\Bigg|\dfrac{2*\sqrt{5}}{25 }\Bigg|\\\\\\\boxed{=\dfrac{2*\sqrt{5}}{25 }}\\\\$

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3 years ago

Which inequality represents all values of x for which the product below is defined?

Wewaii [24]

Answer:

Since we want to satisfy both at the same time, "x" must be equal or greater than 6.

Step-by-step explanation:

This product is formed by two square roots, since this mathematical operator can only be defined for positive values and zero, the number inside the root must be always greater or equal to 0, on both roots. Therefore:

$x - 6 \geq 0\\x \geq 6$

and

$x + 3 \geq 0\\x \geq -3$

Since we want to satisfy both at the same time, "x" must be equal or greater than 6.

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3 years ago

The diagram shows how cos θ, sin θ, and tan θ relate to the unit circle. Copy the diagram and show how sec θ, csc θ, and cot θ r

DIA [1.3K]

Copy the diagram and show how sec θ, csc θ, and cot θ relate to the unit circle.

The representation of the diagram is shown if Figure 1. There's a relationship between sec θ, csc θ, and cot θ related the unit circle. Lines green, blue and pink show the relationship.

a.1 First, find in the diagram a segment whose length is sec θ.

The segment whose length is sec θ is shown in Figure 2, this length is the segment $\overline{OF}$ , that is, the line in green.

a.2 Explain why its length is sec θ.

We know these relationships:

(1) $sin \theta=\frac{\overline{BD}}{\overline{OB}}=\frac{\overline{BD}}{r}=\frac{\overline{BD}}{1}=\overline{BD}$

(2) $cos \theta=\frac{\overline{OD}}{\overline{OB}}=\frac{\overline{OD}}{r}=\frac{\overline{OD}}{1}=\overline{OD}$

(3) $tan \theta=\frac{\overline{FD}}{\overline{OC}}=\frac{\overline{FC}}{r}=\frac{\overline{FC}}{1}=\overline{FC}$

Triangles ΔOFC and ΔOBD are similar, so it is true that:

$\frac{\overline{FC}}{\overline{OF}}= \frac{\overline{BD}}{\overline{OB}}$ 

∴ $\overline{OF}= \frac{\overline{FC}}{\overline{BD}}= \frac{tan \theta}{sin \theta}= \frac{1}{cos \theta} \rightarrow \boxed{sec \theta= \frac{1}{cos \theta}}$ 

b.1 Next, find cot θ

The segment whose length is cot θ is shown in Figure 3, this length is the segment $\overline{AR}$ , that is, the line in pink.

b.2 Use the representation of tangent as a clue for what to show for cotangent.

It's true that:

$\frac{\overline{OS}}{\overline{OC}}= \frac{\overline{SR}}{\overline{FC}}$

But:

$\overline{SR}=\overline{OA}$
$\overline{OS}=\overline{AR}$

Then:

$\overline{AR}= \frac{1}{\overline{FC}}= \frac{1}{tan\theta} \rightarrow \boxed{cot \theta= \frac{1}{tan \theta}}$

b.3 Justify your claim for cot θ.

As shown in Figure 3, θ is an internal angle and ∠A = 90°, therefore ΔOAR is a right angle, so it is true that:

$cot \theta= \frac{\overline{AR}}{\overline{OA}}=\frac{\overline{AR}}{r}=\frac{\overline{AR}}{1} \rightarrow \boxed{cot \theta=\overline{AR}}$

c. find csc θ in your diagram.

The segment whose length is csc θ is shown in Figure 4, this length is the segment $\overline{OR}$ , that is, the line in green.