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ANEK [815]
3 years ago
14

You have exatly 200 feet of fencing to enclose 2 adjacent square regions. assuming you use all the fencing provided what will th

e total area of the enclosures be?
Mathematics
1 answer:
bekas [8.4K]3 years ago
7 0
Adjacent so that means 1 wall will be shared

each square has 4 sides,
but they share a side so 4+4-1=7 sides total

200 divided by 7 sides=200/7 ft per side

the area of a square is side^2
side=200/7
so area=(200/7)^2=40000/49
that's for 1 square
times 2
80000/49 square feet
about 1632.6530612244897959183673469388 square feet
rounded is 1633 square feet

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First to find the radius, you would need to divide the diameter, 26, by half, which in this case its 13.

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3 years ago
The rectangle shown has a perimeter of 146 cm and the given area. Its length is 7 more than five times its width. Write and solv
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Answer:

System of equations:

L = 5W + 7

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Step-by-step explanation:

Given the measurements and key words/phrases in the problem, we can set up two different equations that can be used to find both variables, length and width, of the rectangle.  

The formula for perimeter of a rectangle is:  2W + 2L = P, where W = width and L = length.  We also know that the L is '7 more than five times its width'.  This can be written as:  L = 5W + 7.  Using this expression for the value of 'L', we can use the formula for perimeter and solve for width:

2W + 2(5W + 7) = 146

Distribute:  2W + 10W + 14 = 146

Combine like terms:  12W + 14 = 146

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Divide 12 by both sides:  12W/12 = 132/12 or W = 11

Put '11' in for W in the equation for 'L':  L = 5(11) + 7 or L = 55 + 7 = 62.

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Answer:

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Answer:

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