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pishuonlain [190]
3 years ago
6

Every _____ tessellates

Mathematics
1 answer:
Charra [1.4K]3 years ago
4 0

Answer:

Every <u>hexagon </u>tessellates.

Step-by-step explanation:

Hexagons always tessellates when perfectly combined and aligned especially when the x sides and the y sides are parallel to each other.

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Write the absolute value inequality in the form lx-bl c that has the solution set x&lt;-5 or x&lt;7
irinina [24]
The answer is 5€7=47
4 0
3 years ago
PLS help ASAP I need help with 13
bekas [8.4K]

Answer:

335

Step-by-step explanation:

536/336 = x/210

7 0
3 years ago
Read 2 more answers
I need help pls<br> 11+4b=8b-13<br> b=?
spin [16.1K]
With this, you need side A to equal side B. Your first step is to move the variable to one side. (I've also worked in out, and color coordinated the steps, so you can see better).

11 + 4b = 8b - 13 < let's subtract "4b" from the left side to get rid of it (we're subtracting because it is added on to left side). This will give us:

11 = 8b - 13 < we've subtracted "4b" from the left side, however what you do to one side of the equal sign, you must do to the other, so subtract "4b" from the right side as well. Once done, you should have this"

11 = 4b - 13 < we have "4b-13" because you can only work with like terms. 8b-4b=4b, and the 13 stays untouched.
 
Now let's work on isolating the variable. See how we have a -13 on the side with the variable? We don't want that, so we're going to add 13 to that side, to give us 0 and cancel it out. Remember, what you do to one side, you must do to the other, so add 13 to the 11 on the other side as well. This will give you 24, and your equation should now look like this:

24 = 4b < we're almost done, but the variable is not quite by itself yet. We need to get rid of the "4" in "4b". 4 in being multiplied to "b" so we need to do the opposite operation to cancel it out. We need that 4 to be a 1 because 1x=x. So, divide 4b by 4 to get 1b or just plain b. 

Remember, what you do to one side, you must do to the other, so divide 24 by 4 to get 6, and you're left with your answer.

Answer 6 = b 

Hope this helps!
      

4 0
3 years ago
Which expression is equivalent to the expression below? StartFraction m + 3 Over m squared minus 16 EndFraction divided by Start
Kamila [148]

Option B: \frac{1}{(m-4)(m-3)} is the correct answer.

Explanation:

The given expression is \frac{(\frac{m+3}{m^2-16}) }{(\frac{m^2-9}{m+4} )}

Simplifying the expression, we have,

\frac{m+3}{m^{2}-16}\times\frac{m+4}{m^2-9}

Factor the equations, m^{2}-16\right and m^{2}-9,we get,

m^{2}-16\right=m^{2}-4^{2}=(m+4)(m-4)

m^{2}-9=m^{2}-3^2=(m+3)(m-3)

Substituting these factored expressions in the above expression, we have,

\frac{m+3}{(m+4)(m-4)}\times\frac{m+4}{(m+3)(m-3)}

Cancelling the common terms m+3 and m+4 , we get,

\frac{1}{(m-4)(m-3)}

Thus, the expression equivalent to \frac{(\frac{m+3}{m^2-16}) }{(\frac{m^2-9}{m+4} )} is \frac{1}{(m-4)(m-3)}

Hence, Option B is the correct answer.

3 0
3 years ago
Read 2 more answers
The amount of candy left in a Halloween bucket is given by the function A(t) = 50(0.8)t where t stands for the number of minutes
natulia [17]
I think that equation is supposed to look like this:
A(t)=50(.8) ^{t}
The reason I say that is because this is an exponential decay problem, with a starting amount of 50 pieces of candy.
If that's the case, then it would look like this with a t value of 5:
A(5)=50(.8) ^{5}
and A(5)=50(.32768)
so the amount of candy left after 5 minutes is 16.384 or 16
8 0
3 years ago
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