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Alisiya [41]
3 years ago
5

Please help I do not get

Mathematics
2 answers:
katen-ka-za [31]3 years ago
8 0

Answer:

(a) 51%

(b) 41%

Step-by-step explanation:

We can simplify this problem down by realizing that the amount of girls over 200 will get us our percentage as a decimal.

Looking at this table, we can see that 30+72=102 girls were asked. So, 102\div200=0.51, and 0.51\cdot100=51.

We can also see that 30+52=82 people preferred video games, so 82\div200=0.41, and 0.41\cdot100=41.

Hope this helped!

Anit [1.1K]3 years ago
8 0

Answer:

\Large \boxed{\mathrm{(a) \ 51\% }} \\ \\ \Large \boxed{\mathrm{(b) \ 41\%}}

Step-by-step explanation:

(a) To find the percentage of the students that are girls:

\displaystyle \sf \frac{total \ number \ of \ girls}{number \ of \ students }

\displaystyle \sf \frac{30+72}{200 }= \frac{102}{200 } =51\%

(b) To find the percentage of students that prefer playing video games:

\displaystyle \sf \frac{total \ number \ of \ students \ that \ prefer \ playing \ video \ games}{number \ of \ students }

\displaystyle \sf \frac{30+52}{200 }=\frac{82}{200} = 41\%

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iogann1982 [59]
<span>Form a sequence that has two arithmetic means between -13 and 89. a. -13, 33, 43, 89 c. -13, 21, 55, 89 b. -18, -36, -72, -144 d. -18, -81, -144

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