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3 years ago

I WILL GIVE BRAINLEST!!!!!!

1 answer:

4 0

Can Smart people Answer this plz.??????? I WILL GIVE BRAINLEST!!!!!!

Frank earned x dollars the first week of his new job. He earned 5% more the
second week than the first week. Which expression represents the total amount of
money Frank earned for both weeks?
A. 1.50x
B. 1.05x
C. 2.00x
D. 2.05x

PLSSS SHOW YOUR WORK PLSSSS

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I really need help with this pleaseeee

Sedaia [141]

Answer:

σ = 11.68

Step-by-step explanation:

$σ = \sqrt{ \frac{Σ{(xi - μ)}^{2} }{N} } \\ where \: σ = population \: standard \: deviation \\ xi = each \: value \: from \: population \\ μ = population \: mean \\ N = size \: of \: population$

$σ = \sqrt{ \frac{Σ{(9 - 26)}^{2} + {(16 - 26)}^{2} +{(30 - 26)}^{2} +{(35 - 26)}^{2} + {(40 - 26)}^{2}}{5} } \\ σ = \sqrt{ \frac{Σ{((-17)}^{2} + {(- 10) }^{2} +{(4) }^{2} +{(9) }^{2} +{(14) }^{2})}{5}} \\ σ = \sqrt{ \frac{Σ ({289} + {100} +{16} +{81} + {196})}{5} } \\ σ = \sqrt{ \frac{682}{5} } \\ σ = \sqrt{136.4} \\ σ = 11.679041056525\\ σ = 11.68$

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3 years ago

Draw a flow diagram to indicate the different phases in reproduction.

8090 [49]

Answer:

ovulation fertilization cell division implantation conception delivery

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3 years ago

Find the sum of the series and show your process for finding each term leading to the final sum.

Crazy boy [7]

ANSWER

$\sum_{k=3}^5( - 2k + 5) = - 9$

EXPLANATION

The given series is

$\sum_{k=3}^5( - 2k + 5)$

This series is finite.

The expanded form is

$\sum_{k=3}^5( - 2k + 5) = ( - 2 \times 3 + 5) + ( - 2 \times 4 + 5) + ( - 2 \times 5 + 5)$

This simplifies to

$\sum_{k=3}^5( - 2k + 5) = ( - 6 + 5) + ( - 8+ 5) + ( - 10+ 5)$

$\sum_{k=3}^5( - 2k + 5) = ( - 1) + ( - 3) + ( - 5)$

$\sum_{k=3}^5( - 2k + 5) = - 9$

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3 years ago

PQR is a right-angled triangle.

Mademuasel [1]

X= 20.9

Sin^-1(5/14)

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3 years ago

an outlier may be defined as a data point that is more than 1.5 times the interquartile range below the lower quartile or is mor

Ira Lisetskai [31]

Supposing a normal distribution, we find that:

The diameter of the smallest tree that is an outlier is of 16.36 inches.

--------------------------------

We suppose that tree diameters are normally distributed with mean 8.8 inches and standard deviation 2.8 inches.

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean.
After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem: