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marishachu [46]
3 years ago
5

A diver dives off of a raft - what happens to the diver? the raft? how does this relate to newton's third law? action force: ___

____________ reaction force: _____________
Physics
2 answers:
svetlana [45]3 years ago
7 0

1.      The diver transfers forward and dives into the water.

2.      The raft transfers backwards in the water for the reason that of the reaction force.

3.      The action force is the diver pushing off of the raft; and the

4.      reaction force is the raft pushing back on the diver (causing the diver to go forward and into the water)

kondaur [170]3 years ago
5 0
<span>Actually newtons third law says for every action there is an equal and opposite reaction, Hence here in this case, the diver diving of a raft is the action, after which surely reaction should come in the form where the raft and the driver will rebound with same speed back, and hence here the action force is diving and reaction force is rebounding from the diving place, with same intensity.</span>
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cricket20 [7]

Answer:

100 iPods

Explanation:

The deciBell scale is logarithmic, and thus, it turns multiplying into adding.

Initially, it was the Bell scale, purely logarithmic, where "times 10" is translated into "plus 1" (just like normal logs). However, the steps became too big and so they divided the Bell in 10 parts, the deciBell.

The levels above could well have been called 10B and 12B.

Usually, we define the dB scale for intensity as:

I(dB) = 10•log(I)

Thus,

I = 10^(I(dB)/10)

Now 120 dB gives us units of I = 10^(120/10) = 10^12 Pa (assume the dB are measured to 1 Pa) and 100 dB is 10^10 Pa.

Thus, we would need 100 ipods to get the same intensity

8 0
3 years ago
A squirrel jumps into the air with a velocity of 4 m/s at an angel of 50 degrees. What is the maximum height reached by the squi
Debora [2.8K]

Answer:

Explanation:

Assuming the squirrel is jumping off the ground, here's what we know but don't really know...

v₀ = 4.0 at 50.0°

So that's not really the velocity we are looking for. We are dealing with a max height problem, which is a y-dimension thing. Therefore, we need the squirrel's upward velocity, which is NOT 4.0 m/s. We find it in the following way:

v_{0y}=4.0sin(50.0) which gives us that the upward velocity is

v₀ = 3.1 m/s

Moving on here's what we also know:

a = -9.8 m/s/s and

v = 0

Remember that at the very top of the parabolic path, the final velocity is 0. In order to find the max height of the squirrel, we need to know how long it took him to get there. We are using 2 of our 3 one-dimensional equations in this problem. To find time:

v = v₀ + at and filling in:

0 = 3.1 - 9.8t and

-3.1 = -9.8t so

t = .32 seconds.

Now that we know how long it took him to get to the max height, we use that in our next one-dimensional equation:

Δx = v_0t+\frac{1}{2}at^2 and filling in:

Δx = 3.1(.32)+\frac{1}{2}(-9.8)(.32)^2 and using the rules for adding and subtracting sig fig's correctly, we can begin to simplify this:

Δx = .99 - .50 so

Δx = .49 meters

7 0
3 years ago
3.5 g of a hydrocarbon fuel is burned in a vessel that contains 250. grams of water initially at 25.00 C. After the combustion,
kherson [118]

Answer:

3.) 463 J/g

Explanation:

Heat given by the fuel is used to increase the temperature of the water

so it is given as

Q = ms\Delta T

here we will have

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now we also know that

s = 4186

so we have

Q = (0.250)(4186)(26.55 - 25)

Q = 1622.075 J

so 3.5 g fuel gives above energy

so per gram of fuel will have total energy given as

Q = \frac{1622.075}{3.5}

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6 0
3 years ago
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The velocity is 300ml in 5 mins
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3 years ago
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monitta

Answer:

force F = 1.66 × 10^{-13} N

Explanation:

given data

proton and an electron = 865 nm

solution

we get here force that is express as

force F = k q1 q2 ÷ r²      ......................1

put here value and we get

force F = 9 × 10^{9} × \frac{1.6\times (10^{-19})^{2}}{865 \times (10^{-9})^{2}}    

force F = 1.66 × 10^{-13} N

4 0
3 years ago
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