Answer:
Bowling Ball: weight on Earth = 49 N
Textbook: Mass = 2 kg; weight on the moon = 3.2 N
Large dog: weight on Earth = 490 N; weight on the moon = 80 N
Law of Universal Gravitation: 
= gravitational force (Newtons/N)
<em>G</em> = gravitational constant, 6.67430 × 10¹¹ 
<em>m</em>₁ and <em>m</em>₂ = masses of two objects (kilograms/kg)
<em>r</em>² = square of distance between centers of the two objects (meters/m)
Have a fantastic day!
Answer:
The water is flowing at the rate of 28.04 m/s.
Explanation:
Given;
Height of sea water, z₁ = 10.5 m
gauge pressure,
= 2.95 atm
Atmospheric pressure,
= 101325 Pa
To determine the speed of the water, apply Bernoulli's equation;

where;
P₁ = 
P₂ = 
v₁ = 0
z₂ = 0
Substitute in these values and the Bernoulli's equation will reduce to;

where;
is the density of seawater = 1030 kg/m³

Therefore, the water is flowing at the rate of 28.04 m/s.
Answer:
Entropy is increasing. Entropy is decreasing.
Explanation:
The Entropy doesn't change.
Answer:
(4) weight
Explanation:
The centripetal force acting on the space shuttle in orbit is given by:

where
m is the mass of the shuttle
v is the tangential speed of the shuttle
r is the radius of its circular orbit
When the shuttle orbits the Earth, the centripetal force that keeps the shuttle in circular motion is given by the gravitational attraction between the shuttle and the Earth, which corresponds to the weight of the shuttle, and it is given by:

where
G is the gravitational constant
M is the Earth's mass
And this force, therefore, corresponds to the centripetal force.
Star 1 - 4 hours right ascension
Star 2 - 3 hours right ascension
Subtracting hours right ascension
4 hours right ascension - 3 hours right ascension = 1 hours right ascension.
Thus,
star 1 will rise 1 hour before star 2