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deff fn [24]
3 years ago
6

A crate slides down a ramp that makes a 20∘ angle with the ground. To keep the crate moving at a steady speed, Paige pushes back

on it with a 76 N horizontal force. Part A How much work does Paige do on the crate as it slides 4.0 m down the ramp? Express your answer with the appropriate units.
Physics
1 answer:
VMariaS [17]3 years ago
4 0

Answer:

Hence, work done= 287.54 J

Explanation:

Given data:

angle of ramp with the ground θ =20°

force applied = 76 N

work done on the crate to slide down 4 m down the ramp

W= F×d cosθ ( only the cos component of the force will slide the crate down)

W= 76×4×cos20= 287.54 J

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The figure shown above is series combination as the two resistors (bulb) are there which are then connected to the battery
so i conclude from the above options given the option  is B
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3 years ago
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A fixed mass of gas of volume 600cm^3 at a temperature of 30°c is cooled to 0°c. At the same time, the volume is increased by 10
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Use Math-way it is very easy
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3.accuracy is gauged by comparing the measured value of a known standard to its true value. assuming the mass of the water repre
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The glassware with the highest degree of accuracy is 250 mL beaker.

<h3>What is accuracy?</h3>

When in an experiment, a value is measured 5 times, then if the values measured are same for most of the time or like three times out of five, it said to be accurate. The phenomenon is accuracy.

Accuracy compares the experimental value to the theoretical value.

Accepted density of water = 0.99 g/mL

1. 10 mL cylinder

Mass of water = 6.76 g

Volume of water = 6.8 mL

Density = mass /Volume

density = 6.76/6.8 = 0.99412 g/mL

Percentage error = [Observed value - Accepted value/ Accepted value ] x 100

% error = [0.99412 - 0.99 / 0.99 ] x 100

% error = 0.416 %

2. 50 mL cylinder

Mass of water = 24 g

Volume of water = 24.2 mL

density = 24/24.2 = 0.9917 g/mL

Percentage error = [Observed value - Accepted value/ Accepted value ] x 100

% error = [0.9917 - 0.99 / 0.99 ] x 100

% error = 0.172 %

3. 25 mL cylinder

Mass of water = 17 g

Volume of water = 17.1 mL

density = 17/17.1 = 0.99415 g/mL

Percentage error = [Observed value - Accepted value/ Accepted value ] x 100

% error = [0.99415 - 0.99 / 0.99 ] x 100

% error = 0.419 %

4. 250 mL beaker

Mass of water = 35 g

Volume of water = 35.3 mL

density = 35/35.3 = 0.9915 g/mL

Percentage error = [Observed value - Accepted value/ Accepted value ] x 100

% error = [0.9915 - 0.99 / 0.99 ] x 100

% error = 0.152 %

Lesser the percentage error, higher is the accuracy.

Thus, 250 mL beaker has the highest degree of accuracy.

Learn more about accuracy.

brainly.com/question/13099041

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4 0
2 years ago
A physics professor is pushed up a ramp inclined upward at an angle 33.0° above the horizontal as he sits in his desk chair tha
Andru [333]

Answer:

2.51 m/s

Explanation:

Parameters given:

Angle, A = 33°

Mass, m = 90kg

Inclined distance, D = 2m

Force, F = 600N

Initial speed, u = 2.3m/s

From the relationship between work and kinetic energy, we know that:

Work done = change in kinetic energy

W = 0.5m(v² - u²)

We also know that work done is tẹ product of force and distance, hence, net work done will be the sum of the total work done by the force from the students and gravity.

Hence,

W = F*D*cosA - w*D*sinA

w = m*9.8 = weight

=> W = 600*2*cos33 - 90*9.8*2*sin33

W = 45.7J

=> 45.7 = 0.5*m*(v² - u²)

45.7 = 0.5*90*(v² - 2.3²)

45.7 = 45(v² - 5.29)

=> v² - 5.29 = 1.016

v² = 6.306

v = 2.51 m/s

The final velocity is 2.51 m/s

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3 years ago
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Two acrobats flying through the air grab and hold onto each other in midair as part of a circus act.One acrobat has a mass of 60
earnstyle [38]

Answer:

1.36m/s

Explanation:

We are given that

Mass of one acrobat,m_1=60 kg

Mass of another acrobat,m_2=50 kg

v_2=-3 m/s

v_1=5 m/s

We have to find their  velocity immediately after they grab  onto each other.

The collision between two acrobat is inelastic

According to law of conservation of momentum

m_1v_1+m_2v_2=(m_1+m_2)V

Substitute the values

60\times 5+50(-3)=(60+50)V

300-150=110V

V=\frac{300-150}{110}=1.36m/s

4 0
3 years ago
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