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deff fn [24]
3 years ago
6

A crate slides down a ramp that makes a 20∘ angle with the ground. To keep the crate moving at a steady speed, Paige pushes back

on it with a 76 N horizontal force. Part A How much work does Paige do on the crate as it slides 4.0 m down the ramp? Express your answer with the appropriate units.
Physics
1 answer:
VMariaS [17]3 years ago
4 0

Answer:

Hence, work done= 287.54 J

Explanation:

Given data:

angle of ramp with the ground θ =20°

force applied = 76 N

work done on the crate to slide down 4 m down the ramp

W= F×d cosθ ( only the cos component of the force will slide the crate down)

W= 76×4×cos20= 287.54 J

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At some airports there are speed ramps to help passengers get from one place to another. A speed ramp is a moving conveyor belt
Harrizon [31]

Answer:

It will take you 30.8 s to travel the 120 m of the ramp.

Explanation:

Hi there!

The equation for the position of an object moving in a straight line is:

x = x0 + v * t

Where:

x = position at time t

x0 = initial position

v = velocity

t = time

In this case, we will consider the start of the ramp as the origin of our reference system so that x0 = 0.

Now, let´s calculate the speed of the person walking on the ground:

x = v * t

120 m = v * 72 s

v = 120 m / 72 s

v = 1.7 m/s

If you walk on the ramp with that speed, your total speed will be your walking speed plus the speed of the ramp because both are in the same direction. Then, using the equation for the position:

x = v * t

In this case, v = speed of the ramp + walking speed

v = 2.2 m/s + 1.7 m/s = 3.9 m/s

120 m = 3.9 m/s * t

t = 120 m / 3.9 m/s = 30.8 s

It will take you 30.8 s to travel the 120 m

8 0
3 years ago
The direction of an electric field is the direction (5 points) a negative test charge will move in the field a positive test cha
svet-max [94.6K]

Answer:

a positive test charge will move in the field

Explanation:

The direction of an electric field corresponds to the direction of motion of a positive test charge in the electric field. In fact:

- the electric field produced by a positive charge points outwards the charge --> this is because when a positive test charge is placed in this field, it will feel a repulsive force (because two positive charges repel each other), so it will move away from the positive charge that produces the field

- the electric field produced by a negative charge points towards the charge  itself--> this is because when a positive test charge is placed in this field, it will feel an attractive force (because a positive and a negative charge attract each other), so it will move toward the negative charge that produces the field.

4 0
3 years ago
A 2.6 kg rock is dropped from a height of 10 m. With what speed will it strike the ground. Ignore air resistance. Solve using co
timurjin [86]

Answer:

mgh =  \frac{1}{2} m {v}^{2}  \\ v =  \sqrt{2gh}  \\  =  \sqrt{2 \times 9.8 \times 10}  \: m. {s}^{ - 1}

5 0
2 years ago
When looking at a distance-time graph, how could you tell who was the fastest without having to do any math?
Sholpan [36]

Explanation:

The speed of an object can be found from the slope of the line which plots its distance over time. The object in motion's speed can be compared with another by the value of the slope or the steepness of the line. The steeper the slope is, the greater the speed.

3 0
2 years ago
A solenoidal coil with 22 turns of wire is wound tightly around another coil with 330 turns. The inner solenoid is 21.0 cm long
forsale [732]

Answer:

0.00027646\ T

2.33\times 10^{-5}\ H

-0.04194 V

Explanation:

N_2 = Number of turns in outer solenoid = 330

N_1 = Number of turns in inner solenoid = 22

I_1 = Current in inner solenoid = 0.14 A

\dfrac{dI_2}{dt} = Rate of change of current = 1800 A/s

\mu_0 = Vacuum permeability = 4\pi \times 10^{-7}\ H/m

r = Radius = 0.0115 m

Magnetic field is given by

B=\mu_0\dfrac{N_2}{l}I\\\Rightarrow B=4\pi \times 10^{-7}\times \dfrac{330}{0.21}\times 0.14\\\Rightarrow B=0.00027646\ T

The  average magnetic flux through each turn of the inner solenoid is 0.00027646\ T

Magnetic flux is given by

\phi=BA\\\Rightarrow \phi=0.00027646\times \pi 0.0115^2\\\Rightarrow \phi=1.14862\times 10^{-7}\ wb

Mutual inductance is given by

M=\dfrac{N_1\phi}{I}\\\Rightarrow M=\dfrac{22\times 1.14862\times 10^{-7}}{0.14}\\\Rightarrow M=2.33\times 10^{-5}\ H

The mutual inductance of the two solenoids is 2.33\times 10^{-5}\ H

Induced emf is given by

\epsilon=-M\dfrac{dI_2}{dt}\\\Rightarrow \epsilon=-2.33\times 10^{-5}\times 1800\\\Rightarrow \epsilon=-0.04194\ V

The emf induced in the outer solenoid by the changing current inthe inner solenoid is -0.04194 V

3 0
3 years ago
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