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3 years ago

The density of table sugar is 1.59g/cm3 what is the volume of 7.85g of sugar?

Physics

1 answer:

antoniya [11.8K]3 years ago

8 0

Answer: 4.94cm³

Explanation:

Data;

ρ = 1.59g/cm³

mass = 7.85g

volume = ?

density = mass / volume

ρ = m / v

v = m / ρ

v = 7.85 / 1.59

v = 4.94cm³

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What is not a similarity between mars and earth today?

eduard

Answer:

Mars and Earth are two of the planets of the solar system. Some of the ways in which Mars is different from Earth are as follows-

The size of the earth is bigger than Mars as Earth has a radius of nearly 6400 km, whereas Mars has a radius of about 3400 km.

The atmosphere of earth is primarily comprised of gases such as 78% of Nitrogen (N₂), 21% of Oxygen (O₂), 0.03% of Carbon dioxide (CO₂), and 0.9% of Argon (Ar), whereas the atmosphere of Mars is mainly comprised of 95% of CO₂, 3% of molecular N₂, and 2% of Ar.

The surface gravity also marks a contrasting difference as on Mars, the gravity at the surface is only about 38%, in comparison to the gravity at the earth's surface.

6 0

3 years ago

A small water droplet in a mist of air is approximated as being a sphere of diameter 1.25 mil. Calculate the terminal velocity a

shtirl [24]

The terminal velocity as it falls through still air is 4.65154 in/s.

The diameter of small water droplet is 1.25 mil= 1.25×0.0254×10^-3 m

= 3.175 × 10^-5 m

Now the viscosity of still air is η = 1.83× 10⁻⁵ Pa

So the formula for drag force is:

Fd = 6πηrv

where, v is the velocity.

Now to attain terminal velocity acceleration must be zero.

→ W = Fd

ρVg = 6πrηv

ρ × 4/3 πr³×g = 6πrηv

v = 2/9 × ρgr³/ η

v = 2/9 × 10³×9.81×(3.175×10^-3) / 18.6×10^-6

v = 0.1181 m/s

v = 4.65154 in/s

Learn more about terminal velocity here:

brainly.com/question/20409472

#SPJ4

8 0

2 years ago

Suppose you want to make an interferometer with two slits to show the wave nature of light to your friends. The most convenient

nevsk [136]

Answer:

a) the pattern is bright, b) y = 8.25 mm, c) the distance increases with the wavelength increases

Explanation:

This is a team building exercise to perform interference experiments, where the separation of the slits is d = 1 m = 1 10⁻³ m and the distance to the screen L = 1.5 m

Constructive interference occurs when the path difference is equal to an integer number of wavelengths

d sin θ = m λ

a) The center of the two-ray pattern has the same length so the intensity is MAXIMUM, that is, the pattern is bright

b) to find the distance let's use trigonometry

tan θ= y / L

tan θ =sin θ/cos θ= sin θ

because the angles are small

we substitute

y = $\frac{m \lambda L}{d}$

let's calculate

y = 10 550 10⁻⁹ 1.5 / 1 10⁻³

y = 8.25 10⁻³ m

c) for this part the incident light must be white or polychrome light

let's find the distance (y) for some colors, in the first order

Violet λ = 400

y = 1 400 10⁻⁹ 1.5 / 1 10⁻³

y = 6 10⁻⁴ m

green λ = 500 nm

y = 1 500 10⁻⁹ 1.5 / 1 10⁻³

y = 7.5 10⁻⁴ m

yellow λ = 600 nm

y = 1 600 10⁻⁹ 1.5 / 1.10⁻³

y = 9 10⁻⁴ m

lam λ = 700 nm

y = 1 700 10⁻⁹ 1.5 / 1. 10⁻³

y = 1.05 10⁻³ m

violet, green, orange, red

the distance increases with the wavelength increases

d) To find the wavelength we must measure the distance y from the center of the slit for various interference orders and using the equation we can find the wavelength of rationality

4 0

3 years ago

weight of Ali is 500andN.he is standing on the ground with an area of 0.025 m^2 area .we can find pressure under his feet. what

Inessa05 [86]

Answer:

20000 Pa

Explanation:

Pressure is defined as the force per unit area.

Mathematically : P =F/A where F is force and A is area

Force = 500 N

Area= 0.025 m²

P= 500/0.025

P= 20000 Pa

8 0

3 years ago

A flywheel in a motor is spinning at 510 rpm when a power failure suddenly occurs. The flywheel has mass 40.0 kg and diameter 75

8_murik_8 [283]

Complete Question

A flywheel in a motor is spinning at 510 rpm when a power failure suddenly occurs. The flywheel has mass 40.0 kg and diameter 75.0 cm . The power is off for 40.0 s , and during this time the flywheel slows down uniformly due to friction in its axle bearings. During the time the power is off, the flywheel makes 210 complete revolutions. At what rate is the flywheel spinning when the power comes back on(in rpm)? How long after the beginning of the power failure would it have taken the flywheel to stop if the power had not come back on, and how many revolutions would the wheel have made during this time?

Answer:

$\theta=274rev$