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Paul [167]
3 years ago
10

Which is the most specific classification for the element uranium?

Chemistry
2 answers:
sattari [20]3 years ago
8 0

Explanation:

Uranium is an actinide metal.

Classification of Uranium:

  • Color = Silvery white.
  • Atomic weight = 238.0298gm.
  • State = Solid.
  • Melting point = 1135 degree celcius and 1408 kelvin.
  • Boiling point = 4130 degree celcius and 4403 kelvin.
  • Electron = 92.
  • Protons = 92.
  • Neutrons in most abundant isotopes = 146.

Uranium is the heaviest and naturally occuring metal, last in the periodic table. It is radioactive element, isotopes of uranium that is uranium235 and uranium239 are used used in making atom bombs and nuclear bombs and it follows the uncontrolled chain reaction.

Katena32 [7]3 years ago
3 0
<span>O-Non conductor Ge-Semi conductor Mn-Conductor O<Ge<Mn</span>
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Read 2 more answers
Be sure to answer all parts.
tangare [24]

Answer:

(a) cesium bromide (CsBr): 9.15 grams

(b) calcium sulfate (CaSO4):  5.85 grams

(c) sodium phosphate (Na3PO4): 7.05 grams

(d) lithium dichromate (Li2Cr2O7):  9.88 grams

(e) potassium oxalate (K2C2O4):   7.15 grams

Explanation:

<u>(a) cesium bromide (CsBr):</u>

Molar mass of CsBR = 212.81 g/mol

Number of moles = molarity * volume

Number of moles = 0.100 M *0.43 L

Number of moles = 0.043 moles

Mass of CsBr required = moles * Molar mass

Mass of CsBr required = 0.043 moles * 212.81 g/mol

Mass of CsBr required = 9.15 grams

<u>(b) calcium sulfate (CaSO4):</u>

Molar mass of CaSO4 = 136.14 g/mol

Mass of CaSO4 required = moles * Molar mass

Mass of CaSO4 required = 0.043 moles * 136.14 g/mol

Mass of CaSO4 required = 5.85 grams

<u>(c) sodium phosphate (Na3PO4):</u>

Molar mass of Na3PO4 = 163.94 g/mol

Mass of Na3PO4 required = moles * Molar mass

Mass of Na3PO4 required = 0.043 moles * 163.94 g/mol

Mass of Na3PO4 required = 7.05 grams

<u>(d) lithium dichromate (Li2Cr2O7):</u>

Molar mass of Li2Cr2O7 = 229.87 g/mol

Mass of Li2Cr2O7 required = moles * Molar mass

Mass of Li2Cr2O7 required = 0.043 moles * 229.87 g/mol

Mass of Li2Cr2O7 required = 9.88 grams

<u>(e) potassium oxalate (K2C2O4):</u>

Molar mass of K2C2O4 = 166.22 g/mol

Mass of K2C2O4 required = moles * Molar mass

Mass of K2C2O4 required = 0.043 moles * 166.22 g/mol

Mass of K2C2O4 required = 7.15 grams

7 0
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Answer:

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