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Ganezh [65]
4 years ago
8

a pot is filled with soup. the soup at the bottom of the pot is warmed by the stove burner, but how does the soup at the top get

hot?
Chemistry
1 answer:
Fudgin [204]4 years ago
7 0
The heated soup moves to the tip by convection
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If the equilibrium concentration of CO is 3.4 × 10–1 M, and the equilibrium concentration
Irina18 [472]

Answer:

4.1M = [CH₃OH]

Explanation:

The equilibrium produced for the reaction between CO and H₂ to form CH₃OH is:

CO + 2 H₂ ⇄ CH₃OH

Where Keq is defined as:

Keq = 26 = [CH₃OH] / [CO] [H₂]²

<em>For concentrations in equilibrium</em>

Replacing in Keq the equilibrium concentrations of CO and H₂, the equilibrium concentration of CH₃COOH is:

26 = [CH₃OH] / [3.4x10⁻¹M] [6.8x10⁻¹M]²

<em>4.1M = [CH₃OH]</em>

5 0
4 years ago
Read 2 more answers
A major source of today's medicines
Arada [10]
A major source is coal
5 0
3 years ago
How many liters of oxygen are required to react completely with 1.2 liters of hydrogen to form water? 2H2(g) + O2(g) → 2H2(g)
Ira Lisetskai [31]

Answer:

\boxed{\text{0.60 L}}

Explanation:

We can use Gay-Lussac's Law of Combining Volumes to solve this problem.

Gases at the same temperature and pressure react in the same ratios as their coefficients in the balanced equation.

1. Write the chemical equation.

Ratio: 2 L     1 L

           2H₂ + O₂ → 2H₂O

V/L:   1.2

2. Calculate the volume of O₂.

According to Gay-Lussac, 1 L of O₂ forms from 2 L of H₂.

Then, the conversion factor is (1 L O₂/2 L H₂).

\text{Volume of O}_{2} = \text{1.20 L H}_{2}\times \dfrac{\text{1 L O}_{2}}{\text{2 L H}_{2}} = \textbf{0.60 L O}_{2}\\\\\text{You need }\boxed{\textbf{0.60 L of O}_{2}}

4 0
3 years ago
Which word is used describe someone who is fair and has no bias?
rodikova [14]
Impartial is the word that you want to use
6 0
3 years ago
Read 2 more answers
Assume that the complete combustion of one mole of glucose, a monosaccharide, to carbon dioxide and water liberates 2870 kJ2870
Lubov Fominskaja [6]

Answer:

number of moles of the compound \approx 53 mole

Explanation:

Given that:

The total energy liberated = - 2870 kJ  ( here , the negative sign typical implies the release of energy due to the combustion reaction)

The equation of the reaction can be represented as:

\mathbf{C_6H_{12}O_6_{(s)} + 6O_{2(g)} \to 6CO_{2(g)}+6H_2O_{(l)}}

The energy needed to synthesize 1 mole of compound X  = - 54.1 kJ.mol

Thus;

The total energy = numbers of moles of compound × Energy needed to synthesize  1 mole of compound X

Making the numbers of moles of the compound the subject; we have;

numbers of moles of compound = numbers  \ of \  moles  \ of \  compound =  \dfrac{total \ energy }{Energy \  needed  \ to  \ synthesize \   1  \ mole \  of \  compound  \ X}numbers  \ of \  moles  \ of \  compound =  \dfrac{-2870  \ kJ }{-54.1  \ kJ/mol}

number of moles of the compound = 53.04990  mole

number of moles of the compound \approx 53 mole to two significant figure

7 0
4 years ago
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