Answer:
AgNO₃ will be the limiting reagent.
Explanation:
The balanced reaction is:
AgNO₃ + Li → LiNO₃ + Ag
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate:
- AgNO₃: 1 mole
- Li: 1 mole
- LiNO₃: 1 mole
- Ag: 1 mole
To determine the limiting reagent, you can use a simple rule of three as follows: if by stoichiometry AgNO₃, how much moles of AgNO₃ will be needed if 0.35 moles of Li react?
moles of AgNO₃= 0.35
But 0.35 moles of AgNO₃ are not available, 0.30 moles are available. Since you have less moles than you need to react with 0.35 moles of Li, <u><em>AgNO₃ will be the limiting reagent.
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Answer:
C. Barium n F. Cesium
Explanation:
Because you can feel it or see it in the sky
Its an example of elctronegativity hope this helped
Answer:
CH₄(g) + 2O₂(g) ---> 1CO₂(g) + 2H₂O(g)
Explanation:
any combustion of a hydrocarbon equation is in form:
CₓHₐ(g) + BO₂(g) ---> YCO₂(g) + ZH₂O(g), where x,a,b,y,z are all whole number positive integers
there will be 1 CO₂ to 2 H₂O, since there is 1 C to 4 H in CH₄; it is not 1:4 since 2 H is needed in H₂O
CH₄(g) + _O₂(g) ---> 1CO₂ + 2H₂O
there is 4 total O on products side, which can make 2O₂
CH₄(g) + 2O₂(g) ---> 1CO₂(g) + 2H₂O(g)