Answer:
4.1M = [CH₃OH]
Explanation:
The equilibrium produced for the reaction between CO and H₂ to form CH₃OH is:
CO + 2 H₂ ⇄ CH₃OH
Where Keq is defined as:
Keq = 26 = [CH₃OH] / [CO] [H₂]²
<em>For concentrations in equilibrium</em>
Replacing in Keq the equilibrium concentrations of CO and H₂, the equilibrium concentration of CH₃COOH is:
26 = [CH₃OH] / [3.4x10⁻¹M] [6.8x10⁻¹M]²
<em>4.1M = [CH₃OH]</em>
Answer:
Explanation:
We can use Gay-Lussac's Law of Combining Volumes to solve this problem.
Gases at the same temperature and pressure react in the same ratios as their coefficients in the balanced equation.
1. Write the chemical equation.
Ratio: 2 L 1 L
2H₂ + O₂ → 2H₂O
V/L: 1.2
2. Calculate the volume of O₂.
According to Gay-Lussac, 1 L of O₂ forms from 2 L of H₂.
Then, the conversion factor is (1 L O₂/2 L H₂).

Impartial is the word that you want to use
Answer:
number of moles of the compound
53 mole
Explanation:
Given that:
The total energy liberated = - 2870 kJ ( here , the negative sign typical implies the release of energy due to the combustion reaction)
The equation of the reaction can be represented as:

The energy needed to synthesize 1 mole of compound X = - 54.1 kJ.mol
Thus;
The total energy = numbers of moles of compound × Energy needed to synthesize 1 mole of compound X
Making the numbers of moles of the compound the subject; we have;
numbers of moles of compound = 

number of moles of the compound = 53.04990 mole
number of moles of the compound
53 mole to two significant figure