All categories

3 years ago

Evans dog weighs 63 pounds. Oxanas dog weighs 9 pounds. How much more does evan’s dog weigh than oxanas dog?

Mathematics

2 answers:

natima [27]3 years ago

7 0

Answer:54pounds

Step-by-step explanation:63-9=54

tatyana61 [14]3 years ago

5 0

Answer: Yes, the answer is 54.

You might be interested in

95 is 95% of what number?

Serggg [28]

95% * x = 95

95/100 * x = 95

0,95 * x = 95

0,95x = 95 / : 0,95

x = 100

3 0

3 years ago

Read 2 more answers

The logarithmic expression ln(√e/y^3) can be rewritten as

kvv77 [185]

Answer:

$\dfrac{1 - 6 \ln y}{2}$

Step-by-step explanation:

$\ln \dfrac{\sqrt{e}}{y^3} =$

$= \ln \dfrac{e^\frac{1}{2}}{y^3}$

$= \ln e^\frac{1}{2} - \ln y^3$

$= \dfrac{1}{2} \ln e - 3 \ln y$

$= \dfrac{1}{2} - 3 \ln y$

$= \dfrac{1 - 6 \ln y}{2}$

6 0

3 years ago

An expression is shown below: 2x3y + 18xy − 10x2y − 90y Part A: Rewrite the expression by factoring out the greatest common fact

SCORPION-xisa [38]

Answer:

Part A : 2y( x³ + 9x - 5x² - 45 ), Part B : 2y( x - 5 )( x² + 9 )

Step-by-step explanation:

Part A : Let's break every term down here to their " prime factors ", and see what is common among them,

2x³y + 18xy − 10x²y − 90y -

2x³y = 2 $*$ x³ $*$ y,

18xy = 2 $*$ 3 $*$ 3 $*$ x $*$ y,

− 10x²y = 2 $*$ - 5 $*$ x² $*$ y, - so as you can see for this example I purposely broke down - 10 into 2 and - 5. I could have placed the negative on the 2, but as that value was must likely common among all the terms, I decided to place it on the 5. The same goes for " − 90y. " I placed the negative there on the 5 once more.

− 90y = 2 $*$ - 5 $*$ 3 $*$ 3 $*$ y

The terms common among each term are 2 and y. Therefore, the GCF ( greatest common factor ) is 2x. Let's now factor the expression using this value.

2y( x³ + 9x - 5x² - 45 )

Part B : Let's simply factor this entire expression. Of course starting with the " factored " expression : 2y( x³ + 9x - 5x² - 45 ),

$2y\left(x^3+9x-5x^2-45\right)$ - Factor out " $(x^3+9x-5x^2-45\right))$ " by grouping,

$\left(x^3-5x^2\right)+\left(9x-45\right)$ - Factor 9 from 9x - 45 and x² from x³ - 5x²,

$9\left(x-5\right)+x^2\left(x-5\right)$ - Factor out common term x - 5,

$\left(x-5\right)\left(x^2+9\right)$ - And our solution is thus 2y( x - 5 )( x² + 9 )

3 0

4 years ago

What is the product of 3y<br> product of (3y^)(274)

Dima020 [189]

3y^-4 × (2y^-4) = 6y^-8

= 6/1/y^8

= 6/y^8

.................................................

1) When x^1 multiply with x^2, 1 will add to 2 and become 3

= x^3

2) y^-1 = 1/y

3^-2 = 1/3^2 = 1/9

5^-2 = 1/5^2 = 1/25

5 0

3 years ago

A teacher administers three different versions of a test to his students. The two-way table shows the results. Find each probabi

kakasveta [241]

The P(pass | Test A) is 31.81%, P(pass | Test B) is 29.87%, and P(pass | Test C) is 22.07%

<h3>What is probability?</h3>

It is defined as the ratio of the number of favourable outcomes to the total number of outcomes, in other words, the probability is the number that shows the happening of the event.

Part A:

Total number of students = 154

Total number of students passed the test = 49

The probability:

P(pass | Test A) = 49/154 = 31.81%

Part B:

Total number of students = 154

Total number of students passed the test = 46

The probability:

P(pass | Test B) = 46/154 = 29.87%

Similarly, for the probability:

P(pass | Test C) = 34/154 = 22.07%

Thus, the P(pass | Test A) is 31.81%, P(pass | Test B) is 29.87%, and P(pass | Test C) is 22.07%

Learn more about the probability here:

brainly.com/question/11234923

#SPJ1

5 0

3 years ago