3 years ago

If x^2+y^2=73 and xy=24, what is the value of (x+y)^2? And Why?

Mathematics

1 answer:

nydimaria [60]3 years ago

7 0

(x+y)^2=x^2+y^2+2xy=73+2*24=73+48=121

⇒ (x+y)^2=121

You might be interested in

Graph the function. Then, identify the domain and range of the function.<br> f (x) = (x + 3)^1/2+ 1

DanielleElmas [232]

Answer:x=5

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

**PLEASE HELP**

maksim [4K]

Answer:

Number 4

Step-by-step explanation:

Option B would yield more in the short term but after Option A surpasses it, it would become more profitable.

6 0

2 years ago

Please help me it is due tomorrow

larisa86 [58]

It should be H.13, sorry if this not 100% correct

7 0

3 years ago

Read 2 more answers

Find the slope of the line between the ordered pair (−1,4)and(4,−1) what is the answer??? please answer correctly

luda_lava [24]

9514 1404 393

Answer:

-1

Step-by-step explanation:

The slope formula works nicely for this.

m = (y2 -y1)/(x2 -x1)

m = (-1 -4)/(4 -(-1)) = -5/5 = -1

The slope of the line between the given points is -1.

3 0

2 years ago

H(x)=2x-4/3<br> o h^-1(x)= 3x-12/2<br> o h^-1(x)= 3/(2x-4)<br> o h^-1(x)= 3x+4/2

Fed [463]

Answer:

$\large\boxed{h^{-1}(x)=\dfrac{3x+4}{2}}$

Step-by-step explanation:

$h(x)=\dfrac{2x-4}{3}\to y=\dfrac{2x-4}{3}\\\\\text{Exchange x to y and vice versa}:\\\\x=\dfrac{2y-4}{3}\\\\\text{Solve for y:}\\\\\dfrac{2y-4}{3}=x\qquad\text{multiply both sides by 3}\\\\2y-4=3x\qquad\text{add 4 to both sides}\\\\2y=3x+4\qquad\text{divide both sides by 2}\\\\y=\dfrac{3x+4}{2}$

7 0

2 years ago