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2 years ago

Find each rate and unit rate?

1 answer:

7 0

-60 miles per hour
-12 customers per day
-2.5 meters per second
-$1.59 per pound

You divide the first number by the second number for all of these

You might be interested in

Write the expression in simplest form. (11 + 3) – 2(- 4 1 - 1) = NIO

Aleksandr-060686 [28]

Answer:

11+3=14

-41-1=-42

14-2(-42)

-2(-42)

14+84

I hope this is good enough:

5 0

2 years ago

At the market you can buy 5 bags of apples for $23.60. At the orchard you can get 7 bags of apples for 32.76. Which is the bette

mars1129 [50]

So you want to find the price for 1 apple you find that by dividing so 23.60/5=4.72
and 32.76/7=4.68
so, the 7 bag for 32.76 is the better deal

5 0

2 years ago

Read 2 more answers

How to find the square root of 56 without using a calculator

Olegator [25]

There an old algorythmic method similar to long division:-

7 . 4 8 3
-----------------
) 56. 00 00 00
7 ) 49
  ) ---
   144 ) 7 00
) 576
----
148 8 ) 12400
) 11904
-------
) 496 00
1496 3 ) 44889

THis gives the square root as 7.48 to the nearest hundredth

7 0

2 years ago

Read 2 more answers

Why the order of the coordinates does not matter when calculating length

Rudiy27

The formula for calculating length is:
$\sqrt{ (x_b-x_a)^{2} + (y_b-y_a)^{2} }$

We can also write $x_a - x_b$ or $y_a - y_b$
Why it does not matter?
Let's assume we have 2 numbers, a and b.
When we perform a subtraction:
$a-b$ , we get another number $c$
When we perform another subtraction:
$b-a$ , we get a number $-c$

When we raise $c$ or $-c$ to the power of 2, the result is the same, $c^{2}$ .

4 0

3 years ago

B. Determine the values of a and b so that f is continuous. Please help!

wlad13 [49]

Answer:

following are the solution to this question:

Step-by-step explanation:

Please find the complete question in the attached file.

$\lim_{x\to 2}+f(x) = \lim_{x\to 2}+ (ax^2-bx+3) = 4a-2b+3\\\\ \to 4a-2b+3 = 4\\\\ \therefore \ \ 4a-2b = 1\\\\$

The one-sided limits of F(x) at x = 3 must be equivalent for f(x) to be continuous at x = 3.

$\to \lim_{x\to 3}- f(x) = \lim_{x\to 3}- (ax^2-bx+3) = 9a-3b+3\\\\ \to \lim_{x\to 3}+ f(x) = \lim_{x\to 3}+ (2x-a+b) = 6-a+b\\\\$

So,

$\to 9a-3b+3 = 6-a+b\\\\\therefore\\ \to 10a -4b = 3$

$\to 4a - 2b = 1......(a)\\\to 10a - 4b = 3.......(b)\\$

In equation a multiply the by -2 and then add in the equation b:

$\to -8a + 4b = -2\\\to 10a - 4b = 3\\ \to 2a = 1\\\\ \to a = \frac{1}{2}\\\\ \to \ 4(\frac{1}{2}) - 2b = 1\\\\ \to 2 - 2b = 1\\\\ \to -2b = -1\\\\ \to b = \frac{1}{2}$

So, the value of $a \ and \ b= \frac{1}{2}$

4 0

2 years ago