Question

What is the margin of error for a sample statistic for a population with a standard deviation of 5.75?

Answer 1

Answer:

Margin of error =z-score value for chosen confidence level×population standard deviation

Assuming a 95% confidence level , then

z=1.96

standard deviation=5.75

Margin of error= 1.96×5.75=11.27

Answer 2

Answer:

Step-by-step explanation:

Given that there is a sample statistic for a population.  Population std deviation sigma is given as 5.75.

Margin of error = z critical value * std error

For standard error we must know the sample size n.

Std error = $\frac{\sigma}{\sqrt{n} } =\frac{5.75}{\sqrt{n} }$

Margin of error = Z critical * std error =$1.96*\frac{5.75}{\sqrt{n} }$ for 95%

=$2.58*\frac{5.75}{\sqrt{n} }$ for 99%

Z critical = 1.96 for 95% and 2.58 for 99%

Hence margin of error =