What is 7250 equal to in liters
1 answer:
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Answer:
Only Cory is correct
Step-by-step explanation:
The gravitational pull of the Earth on a person or object is given by Newton's law of gravitation as follows;
Where;
G = The universal gravitational constant
M = The mass of one object
m = The mass of the other object
r = The distance between the centers of the two objects
For the gravitational pull of the Earth on a person, when the person is standing on the Earth's surface, r = R = The radius of the Earth ≈ 6,371 km
Therefore, for an astronaut in the international Space Station, r = 6,800 km
The ratio of the gravitational pull on the surface of the Earth, F₁, and the gravitational pull on an astronaut at the international space station, F₂, is therefore given as follows;
∴ F₁ ≈ 1.14 × F₂
F₂ ≈ 0.8778 × F₁
Therefore, the gravitational pull on the astronaut by virtue of the distance from the center of the Earth, F₂ is approximately 88% of the gravitational pull on a person of similar mass on Earth
However, the International Space Station is moving in its orbit around the Earth at an orbiting speed enough to prevent the Space Station from falling to the Earth such that the Space Station falls around the Earth because of the curved shape of the gravitational attraction, such that the astronaut are constantly falling (similar to falling from height) and appear not to experience gravity
Therefore, Cory is correct, the astronauts in the International Space Station, 6,800 km from the Earth's center, are not too far to experience gravity.
Answer:
32 33-cent stamps, 8 23-cent stamps
Step-by-step explanation:
In order to solve this question, we need to set up a system of equations. Also known as solving for two variables (the number of each stamp).
Let's set x to be the number of 33-cent stamps. Similarly, let's set y to be the number of 23-cent stamps.
To make our first equation, let's think about the number of stamps total we have. We can say:
<em>(AKA - The number of 33-cent stamps, plus the number of 23-cent stamps, equals 40 stamps.)</em>
Now, let's make an equation for the cost of these stamps.
<em>(AKA - The cost of the stamps in total, should equal $12.40).</em>
So now, we have our two equations:
If you have a TI-84 graphing calculator, you can go to apps -> polysmlt2 -> simultaneous eqn solver, and then input these equations into the menu. This will solve the problem for you.
If you need to do this manually, let's use substitution. Condense our first equation to make it more substitutable.
Now, let's put this into our second equation.
Distribute, and solve for y.
Now, we plug this into one of our equations.
In the end, we have thirty-two 33-cent stamps, and eight 23-cent stamps.
