The answer is 6.4×<span>10<span>−<span>5</span></span></span>
2,2,and2 because there are 2 sides of a coin, 2 cards, and 2 marbles
<span>You are given the waiting times between a subway departure schedule and the arrival of a passenger that are uniformly distributed between 0 and 6 minutes. You are asked to find the probability that a randomly selected passenger has a waiting time greater than 3.25 minutes.
Le us denote P as the probability that the randomly selected passenger has a waiting time greater than 3.25 minutes.
P = (length of the shaded region) x (height of the shaded region)
P = (6 - 3.25) * (0.167)
P = 2.75 * 0.167
P = 0.40915
P = 0.41</span><span />
Answer:
try 21
Step-by-step explanation:
if not im as stuck as you are :(
Answer:
the answer is......
Step-by-step explanation:
f ,c,a
