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katrin2010 [14]
3 years ago
9

53/200 write the fraction or mixed number as a percent ....can u please explain how to do the problem....

Mathematics
1 answer:
denis23 [38]3 years ago
7 0
\dfrac{53}{200}\cdot100\%=\dfrac{53}{2}\%=26.5\%
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Prism A is similar to Prism B. The volume of Prism A is 2080 cm³.
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There are two possibilities if no further information is given.
for two similar prisms, if the ratio of sides is a, the ratio of volume is a³
2080/260=8=2³
16640/2080=8=2³
2080/520=4, not a cubic number
2080/1040, not a cubic number
It is either A or D depending on which prism is bigger. 
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You are planning to attend a 2-year college at a cost of $8,278.00/yr for your associate’s degree and then 2 years more at a uni
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10/5 - 4

Step-by-step explanation:

you have to write down what you understand from the sentence.

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10/5 - 4

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3 years ago
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3 years ago
In a class 27 of students, 12 have a cat and 11 have a dog. There are 5 students who have a cat and a dog. What is the probabili
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Answer:

41.67% probability that a student has a dog given that they have a cat

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: having a cat.

Event B: having a dog.

12 of 27 students have a cat:

This means that P(A) = \frac{12}{27}

5 students who have a cat and a dog.

This means that P(A \cap B) = \frac{5}{27}

What is the probability that a student has a dog given that they have a cat?

P(B|A) = \frac{\frac{5}{27}}{\frac{12}{27}} = \frac{5}{12} = 0.4167

41.67% probability that a student has a dog given that they have a cat

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