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borishaifa [10]
3 years ago
5

Carbon monoxide (CO) reacts with hydrogen (H2) to form methane (CH4) and water (H20).

Chemistry
1 answer:
matrenka [14]3 years ago
3 0

Answer: The equilibrium concentration of CH_4 , expressed in scientific notation is 5.9\times 10^{-2}M

Explanation:

Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients.

The given balanced equilibrium reaction is,

                          CO(g)+3H_2(g)\rightleftharpoons CH_4(g)+H_2O(g)

At eqm. conc.     (0.30) M     (0.10) M      (x) M   (0.020) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[CH_4]\times [H_2O]}{[CO]\times [H_2]^3}

Now put all the given values in this expression, we get :

3.90=\frac{x\times (0.020)}{(0.30)\times (0.10)^3}

By solving the term 'x', we get :

x = 0.059 M=  5.9\times 10^{-2}M

Thus, the concentrations of CH_4 at equilibrium is :

Concentration of CH_4 = (x) M  = 5.9\times 10^{-2}M

The equilibrium concentration of CH_4 , expressed in scientific notation is 5.9\times 10^{-2}M

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