Answer:
0 g.
Explanation:
Hello,
In this case, since the reaction between methane and oxygen is:

If 0.963 g of methane react with 7.5 g of oxygen the first step is to identify the limiting reactant for which we compute the available moles of methane and the moles of methane consumed by the 7.5 g of oxygen:

Thus, since oxygen theoretically consumes more methane than the available, we conclude the methane is the limiting reactant, for which it will be completely consumed, therefore, no remaining methane will be left over.

Regards.
Hydrogen bonds are a strong attractive force, since they are less stronger than ionic bonds.
Main sequence stars with low temperatures tend to have low luminosity is based on Hertzprung-Russell diagram
<h3>What is the Hertzsprung-Russell diagram's main sequence?</h3>
The bright, hot stars in the image's upper left are the main sequence group, which stretches roughly diagonally to the lower right (dim and cool). In the bottom left are white dwarfs, which are small, faint, and hot. In the top right are giant and supergiant stars, which are big, bright, and cool.
<h3>What is the main sequence star H-R diagram trend?</h3>
Main sequence stars have a wide range of effective temperatures, but because they are brighter at higher temperatures, they normally follow a band from the bottom right to the top left of the diagram. Inside the cores, hydrogen and helium are fusing together.
To know more about H-R diagram visit:
brainly.com/question/13635125
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Answer:
I beleive the first option is correct