The equation g(x) in vertex form of a quadratic function for the transformations whose graph is a translation 4 units left and 1 unit up of the graph of f(x) is (x-4)² + 1
Given a quadratic function for the transformations given the function f(x) = x²
If the function g(x) of the graph is translated 4 units to the left, the equation becomes (x-4)² (note that we subtracted 4 from the x value
- Translating the graph 1 unit up will give the final function g(x) as (x-4)² + 1 (We added 1 since it is an upward translation.)
Hence the equation g(x) in vertex form of a quadratic function for the transformations whose graph is a translation 4 units left and 1 unit up of the graph of f(x) is (x-4)² + 1
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Answer:
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Step-by-step explanation:
Answer:
We can see that both the triangles are congruent to each other.
So, PQ = TU (CPCT), Thus TU = <u>6</u><u>0</u><u>.</u>
Parent function is y=√x
result is
-4+√(25(x-1))
-4 was added to whole function so translated 4 units down
it every x was multipied by 25 so horizontally stretched bya factor of 25
then, minus 1 from every x to move to right
so the blanks are
strech 25, 1 to the right, 4 down
