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mariarad [96]
3 years ago
14

Factor 8q^2 + 3m + 4qm + 6q=

Mathematics
1 answer:
SIZIF [17.4K]3 years ago
8 0
8q² + 4qm + 6q + 3m
4q(2q) + 4q(m) + 3(2q) + 3(m)
4q(2q + m) + 3(2q + m)
(4q + 3)(2q + m)
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Find the center and radius of this circle x^2+y^2-6x-10y+30=0
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Answer:

The circle's centre is at the position (3, 5), and it has a radius of 2

Step-by-step explanation:

First let's put it in a useful format by completing the squares:

x² + y² - 6x - 10y + 30 = 0

x² - 6x + y² - 10y = -30

x² - 6x + 9 + y² - 10y + 25 = -30 + 9 + 25

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This tells us that the centre position is (3, 5) and the radius is √4, or 2

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3 years ago
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