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cricket20 [7]
3 years ago
9

Pls help .............

Mathematics
2 answers:
aivan3 [116]3 years ago
5 0
B. Because you read it from left to right so it would be y,x.
ryzh [129]3 years ago
3 0
I believe the answer is ab
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PLEASE HELP I think is A or D
Natalka [10]
Looking at the angles of the triangles

N=S
M=R
O=T

so MON would be RTS
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Graph the image of the given triangle under a dilation with a scale factor of 12 and the center of dilation ​ (0, 0) ​ .
PilotLPTM [1.2K]

Answer:

brainly.com/question/10891847

Step-by-step explanation:

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2 years ago
What is the area of this face?
BARSIC [14]

Answer:

10*4-6*2=28

Step-by-step explanation:

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1 year ago
Read 2 more answers
How many 1/3 liters are in 4 2/3 liters
jonny [76]

Answer:

14

Step-by-step explanation:

This is a division problem.

We want to find how many 1/3 liters are in 4⅔ liters.

We divide to obtain:

\frac{4 \frac{2}{3} }{ \frac{1}{3} }

Or

4 \frac{2}{3}  \div  \frac{1}{3}

Convert to improper fraction.

\frac{14}{3}  \div  \frac{1}{3}

\frac{14}{3}  \times  \frac{3}{1}

This simplifies to

14

Therefore there are fourteen ⅓ liters in 4⅔ liters

5 0
3 years ago
g In R simulate a sample of size 20 from a normal distribution with mean µ = 50 and standard deviation σ = 6. Hint: Use rnorm(20
Illusion [34]

Answer:

> a<-rnorm(20,50,6)

> a

[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905

[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501

Then we can find the mean and the standard deviation with the following formulas:

> mean(a)

[1] 50.72451

> sqrt(var(a))

[1] 7.470221

Step-by-step explanation:

For this case first we need to create the sample of size 20 for the following distribution:

X\sim N(\mu = 50, \sigma =6)

And we can use the following code: rnorm(20,50,6) and we got this output:

> a<-rnorm(20,50,6)

> a

[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905

[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501

Then we can find the mean and the standard deviation with the following formulas:

> mean(a)

[1] 50.72451

> sqrt(var(a))

[1] 7.470221

5 0
2 years ago
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