Answer:
q≤7
Step-by-step explanation:
q+8≤15
1) Subtract 8 from both sides:
q≤7
Answer:
ratios equivalent to 1/3=2/6,3/9
Step-by-step explanation:
Double number line is a diagram used when. quantities have different units.
It shows each of the quantities on its own number line with corresponding pairs of values lined up.The values of each number line are not the same unless there is a 1:1 ratio between them.
some ratios equivalent to 1:3 are;
2:6,3:9,4:12,5:15,6:18,7:21,etc
The longest distance between corners inside his closet is 105.3 inches
I think the answer is A but I could be wrong
Consider the expression

To factorize the expression in the denominator we use difference of squares:

To factorize

we use the following method:

where a, b are 2 numbers such that a+b= -1, the coefficient of x,
and a*b= -6, the constant.
such 2 numbers can be easily checked to be -3 and 2
(-3*2=6, -3+2=-1)
So



for x>2

thus
for x>2,

Answer:
for x>2

, (but the expression is never 0)