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3 years ago

How much wrapping is needed for a package that is shaped like a cube 16 in. on each edge?

Mathematics

1 answer:

PtichkaEL [24]3 years ago

3 0

Answer:

1536 in^2

Step-by-step explanation:

This is basically asking for the surface area so knowing that is a cube all the sides are equal so one side would be 16(16) which is 256 in ^2. The knowing that there is 6 sides you would multiply it by 6 which is 256(6)= 1536^2

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If f(x) = x^2 - 25 and g(x) = x - 5, what is the domain of (f/g)(x)

zhuklara [117]

Answer:

The domain of the function is all real numbers except number 5

Step-by-step explanation:

we have

$f(x)=x^{2}-25$

The domain of f(x) is all real numbers

$g(x)=x-5$

The domain of g(x) is all real numbers

$(f/g)(x)=\frac{f(x)}{g(x)}$

substitute

$(f/g)(x)=\frac{x^{2}-25}{x-5}$

Remember that

The denominator cannot be zero

For x=5 the denominator is equal to zero

therefore

The domain of the function is all real numbers except number 5

6 0

3 years ago

Considering only the factors of the form x - k, what is the relationship between the k values and the zeros?

Fudgin [204]

Given:

Considering only the factors of the form x - k.

To find:

The relationship between the k values and the zeros?

Solution:

We know that, if (x-c) is a factor of a function f(x), then x=c is a zero of function f(x), i.e., f(c)=0, where, c is a constant.

It is given that, only the factors of the form x - k. Then by using the above theorem we can say that, k values are the zeros of the function.

The relationship between the k values and the zeros is defined as

k values = Zeros of the function

Therefore, the k values are to zeros of the function.

8 0

2 years ago

--->WORTH 50 POINTS <--- Question in the attachment below. I will give brainiest to best answer. Please show work.

notsponge [240]

Hi there

Root=0.5 means x=0.5

Plug in 0.5 for x
(b-5)0.5^2-(b-2)0.5+b=0
(b-5)0.25-(b-2)035+b=0
Simplify
0.75b-2.25=0
b=3

Hope this helps

7 0

3 years ago

Read 2 more answers

A map using a scale inch of 1 to 5 miles shows a section of land with an area of 3.2 in.² what is the actual area of the section

Karolina [17]

Answer:

The actual area of land is 80 mi² .

Step-by-step explanation:

Given that we have to find the actual area so first we have to square the ratio(scale factor) :

1 in : 5 mi

(1 in)² : (5 mi)²

1 in² : 25 mi²

Next, the actual area will be :

1 in² = 25 mi²

(1 × 3.2) in² = (25 × 3.2) mi²

3.2 in² = 80 mi²

6 0

3 years ago

Solve the following equation simultaneously 1/x-5/y=7, 2/x+1/y=3

maria [59]

Answer:

(x, y) = (1/2, -1)

Step-by-step explanation:

Subtracting twice the first equation from the second gives ...

(2/x +1/y) -2(1/x -5/y) = (3) -2(7)

11/y = -11 . . . . simplify

y = -1 . . . . . . . multiply by y/-11

Using the second equation, we can find x:

2/x +1/-1 = 3

2/x = 4 . . . . . . . add 1

x = 1/2 . . . . . . . multiply by x/4

The solution is (x, y) = (1/2, -1).

_____

<em>Additional comment</em>

If you clear fractions by multiplying each equation by xy, the problem becomes one of solving simultaneous 2nd-degree equations. It is much easier to consider this a system of linear equations, where the variable is 1/x or 1/y. Solving for the values of those gives you the values of x and y.

A graph of the original equations gives you an extraneous solution of (x, y) = (0, 0) along with the real solution (x, y) = (0.5, -1).

6 0

2 years ago