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3 years ago

How much wrapping is needed for a package that is shaped like a cube 16 in. on each edge?

Mathematics

1 answer:

PtichkaEL [24]3 years ago

3 0

Answer:

1536 in^2

Step-by-step explanation:

This is basically asking for the surface area so knowing that is a cube all the sides are equal so one side would be 16(16) which is 256 in ^2. The knowing that there is 6 sides you would multiply it by 6 which is 256(6)= 1536^2

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What is the equivalent to 2 to the 4th power

Paladinen [302]

Answer:

4 to the 2nd power is the equivalent to 2 to the 4th power

Step-by-step explanation:

2⁴ = 16 = 4²

5 0

3 years ago

Read 2 more answers

A square has sides of length s a rectangle is 6 inches shorter and 1 inch longer than the square. Which of the following polynom

harkovskaia [24]

I think the answer is C

5 0

3 years ago

Diego and Lin are drinking milkshakes. Lin starts with 12 ounces and drinks 1/4 an ounce per second. Diego starts with 20 ounces

sammy [17]

Answer:

Lin = 48 seconds

Diego = 30 seconds

Step-by-step explanation:

Hi, to answer this question we have to divide the total ounces of drink by the amount that each one drank per second, for each case.

Mathematically speaking:

Lin = 12 ounces / (1/4) ounces/second = 12/ (1/4) = 48 seconds

Diego = 20 ounces / (2/3) ounces/second = 20/ (2/3) = 30 seconds

Feel free to ask for more if needed or if you did not understand something.

3 0

3 years ago

To test the effectiveness of a business school preparation course, 8 students took a general business test before and after the

Lisa [10]

Solution :

Group Before After

Mean 693.75 743.75

Sd 155.37 143.92

SEM 54.93 50.88

n 8 8

Null hypothesis : The preparation course not effective.

$H_0: \mu_d = 0$

Alternative hypothesis : The preparation course is effective in improving the exam scores.

$H_a : \mu_d>0$ (after - before)

4 0

3 years ago

PLEASE HELP I have been trying to figure this out for a really long time and I want to get the best grade on my test !

Shalnov [3]

Answer:

see below

Step-by-step explanation:

$-4^{2} =-16\\\\-\sqrt{4} =-2\\\\\sqrt{4^{2} } =4\\\\-2\sqrt{4} =-4\\\\(-4)^{2} =16\\\\\sqrt{1/4} =1/2$

so the order

-16

-4

-2

1/2

in root forms and exponent

$-4^{2} \\\\-2\sqrt{4} \\\\-\sqrt{4} \\\\\sqrt{\frac{1}{4} } \\\\\sqrt{4^{2} } \\\\(-4 )^{2}$

8 0

3 years ago