Answer:
I drew more points as uploaded picture.
We have, arc BD + 210 + 90 = 360 deg
(sum of all arcs on circle)
=> arc BD = 360 - 210 - 90 = 60 deg
Here we have angle CBD = (1/2) x arc CD = (1/2) x 90 = 45 deg
(property of angle on circle)
=> angle ABD = angle ABC - angle CBD = 180 - CBD = 180 - 45 = 135 deg
( A, B, C lie on same line => ABC = 180 deg)
Otherwise, we have:
angle BDA = (1/2) x arc BD = (1/2) x 60 = 30 deg
We have: x + angle BDA + angle ABD = 180 deg
(sum of all angles in a triangle)
=> x = 180 - angle BDA - angle ABD
=> x = 180 -135 - 30
=> x = 15 deg
Hope this helps!
:)
<u><em>Answer:</em></u>
<u><em>S L O P E</em></u>
<u><em>Explain:</em></u>
<u><em>S L O P E</em></u>
Answer:
O D. Luis had 6 pencils. He placed them in 4 groups. How many were in each group?
Step-by-step explanation:
this makes more sense, since he had 6 pencils and put them in 4 different groups. so, 6 *4 = 24 c:
Let , a, b and c be the length of three sides of triangle, represented in terms of vectors as 
.
Now, vector of same Magnitude acts as normal vector to each side.
So, equation of any vector p having normal q is given by
Now sum of three vector and it's normal is given as
Cross product of two identical vectors is Zero.
