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3 years ago

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What is the equation of the following line? Be sure to scroll down first to see all answer options. (0,3) (3,0) A. y = -x + 3 B.

y = x + 3 C. y = x - 1 D. y = -x - 3 E. y = -3x + 1 F. y = -3x

1 answer:

qaws [65]3 years ago

4 0

The correct answer is Choice A.

If you plot the points on a graph, you will see that there is a slope of -1 and the y-intercept is (0, 3).

This matches the equation of y = -x + 3 in Choice A.

You might be interested in

Simplify the expression 3+2^2 / 2+3

vredina [299]

Ans

8 option b.

Step-by-step explanation:

3+4/2+3

=3+2+3

=5+3

=8

3 0

2 years ago

If ED = 10 and DB = 3x-8, what is the length of EB<br><br> 1. 32<br> 2. 22<br> 3. 10<br> 4. 20

Debora [2.8K]

Based on the picture, we know that ED is equal to DB. Therefore:

2 times ED=EB
2(10)=20

EB is 20

4 0

3 years ago

Read 2 more answers

Use the rule to write the first five terms of the pattern.

AlekseyPX

Answer:

A =First term of the pattern = 11

To find the first five terms we have to use the rule which is

Add 10 to first term and then subtract 5 from it.Which is equivalent to

= A +10 -5

1. Second Term = 11 + 10 -5

= 21 - 5

=16

→Third term = 16 +10-5

= 26 - 5

= 21

→Fourth term : 21 + 10 - 5

= 31 -5

= 26

→Fifth term : 26 +10 -5

= 36- 5

= 31

→Sixth term:

=31 + 10- 5

= 41 -5

= 36

So, the first five term apart from 11 is 16, 21,26,31,36 which is an Airthmetic progression.

4 0

2 years ago

Read 2 more answers

Use the Polynomial Identity below to help you create a list of 10 Pythagorean Triples:

Stolb23 [73]

Answer:

(3,4,5)

(6,8,10)

(5,12,13)

(8,15,17)

(12,16,20)

(7,24,25)

(10,24,26)

(20,21,29)

(16,30,34)

(9,40,41)

Just choose 2 numbers from {1,2,3,4,5,6,7,8,...} and make sure the one you input for x is larger.

Post the three in the comments and I will check them for you.

Step-by-step explanation:

We need to choose 2 positive integers for x and y where x>y.

Positive integers are {1,2,3,4,5,6,7,.....}.

I'm going to start with (x,y)=(2,1).

x=2 and y=1.

$(2^2+1^2)^2=(2^2-1^2)^2+(2\cdot2\cdot1)^2$

$(4+1)^2=(4-1)^2+(4)^2$

$(5)^2=(3)^2+(4)^2$

So one Pythagorean Triple is (3,4,5).

I'm going to choose (x,y)=(3,1).

x=3 and y=1.

$(3^2+1^2)^2=(3^2-1^2)^2+(2\cdot3\cdot1)^2$

$(9+1)^2=(9-1)^2+(6)^2$

$(10)^2=(8)^2+(6)^2$

So another Pythagorean Triple is (6,8,10).

I'm going to choose (x,y)=(3,2).

x=3 and y=2.

$(3^2+2^2)^2=(3^2-2^2)^2+(2\cdot3\cdot2)^2$

$(9+4)^2=(9-4)^2+(12)^2$

$(13)^2=(5)^2+(12)^2$

So another is (5,12,13).

I'm going to choose (x,y)=(4,1).

$(4^2+1^2)^2=(4^2-1^2)^2+(2\cdot4\cdot1)^2$

$(16+1)^2=(16-1)^2+(8)^2$

$(17)^2=(15)^2+(8)^2$

Another is (8,15,17).

I'm going to choose (x,y)=(4,2).

$(4^2+2^2)^2=(4^2-2^2)^2+(2\cdot4\cdot2)^2$

$(16+4)^2=(16-4)^2+(16)^2$

$(20)^2=(12)^2+(16)^2$

We have another which is (12,16,20).

I'm going to choose (x,y)=(4,3).

$(4^2+3^2)^2=(4^2-3^2)^2+(2\cdot4\cdot3)^2$

$(16+9)^2=(16-9)^2+(24)^2$

$(25)^2=(7)^2+(24)^2$

We have another is (7,24,25).

You are just choosing numbers from the positive integer set {1,2,3,4,... } and making sure the number you plug in for x is higher than the number for y.

I will do one more.

Let's choose (x,y)=(5,1).

$(5^2+1^2)^2=(5^2-1^2)^2+(2\cdot5\cdot1)^2$

$(25+1)^2=(25-1)^2+(10)^2$

$(26)^2=(24)^2+(10)^2$

So (10,24,26) is another.

Let (x,y)=(5,2).

$(5^2+2^2)^2=(5^2-2^2)^2+(2\cdot5\cdot2)^2$

$(25+4)^2=(25-4)^2+(20)^2$

$(29)^2=(21)^2+(20)^2$

So another Pythagorean Triple is (20,21,29).

Choose (x,y)=(5,3).

$(5^2+3^2)^2=(5^2-3^2)^2+(2\cdot5\cdot3)^2$

$(25+9)^2=(25-9)^2+(30)^2$

$(34)^2=(16)^2+(30)^2$

Another Pythagorean Triple is (16,30,34).

Let (x,y)=(5,4)

$(5^2+4^2)^2=(5^2-4^2)^2+(2\cdot5\cdot4)^2$

$(25+16)^2=(25-16)^2+(40)^2$

$(41)^2=(9)^2+(40)^2$

Another is (9,40,41).

5 0

2 years ago

Here’s the answer you need to know

vovikov84 [41]

Thank you sooo much Maddi441

8 0

2 years ago