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ira [324]
4 years ago
9

(40 POINTS, WILL GIVE BRAINLIEST) There are 4 transformations for each function.

Mathematics
1 answer:
nika2105 [10]4 years ago
4 0

f(x) + n - translate the graph n units up

f(x) - n - translate the graph n units down

f(x + n) - translate the graph n units left

f(x - n) - translate the graph n units right

nf(x) - dilation of the graph along the Oy axis and the scale n

f(nx) - dilation of the graph along the Ox axis and the scale 1/n

-f(x) - symmetry of the graph with respect to the Ox axis

f(-x) - symmetry of the graph with respect to the Oy axis

-----------------------------------------------------------------------------------------------------

f(x)=-3\cdot2^{x-1}-1\\\\g(x)=2^x\\\\3g(x)=3\cdot2^x-\text{dilatation by a scale of 3}\\\\-3g(x)=-3\cdot2^x-\text{symmetry of the graph with respect to the Ox axis}\\\\-3g(x-1)=-3\cdot2^{x-1}-\text{translate the graph 1 unit right}\\\\-3g(x-1)-1=f(x)=-3\cdot2^{x-1}-1-\text{translate the graph 1 unit down}


f(x)=-\dfrac{1}{4}\cdot2^{x+1}-1\\\\g(x)=2^x\\\\\dfrac{1}{4}g(x)=\dfrac{1}{4}\cdot2^x-\text{dilatation by a scale of}\ \dfrac{1}{4}\\\\-\dfrac{1}{4}g(x)=-\dfrac{1}{4}\cdot2^x-\text{symmetry of the graph with respect to the Ox axis}\\\\-\dfrac{1}{4}g(x+1)=-\dfrac{1}{4}\cdot2^{x+1}-\text{translate the graph 1 unit left}\\\\-\dfrac{1}{4}g(x+1)-1=f(x)=-\dfrac{1}{4}\cdot2^{x+1}-1-\text{translate the graph 1 unit down}

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-Dominant- [34]
<h3>Answer: x = 1/2</h3>

=========================================================

Explanation:

Recall that quadratic form is ax^2+bx+c.

So we need an x^2 term followed by an x term, then a constant at the end.

It may not look it, but the given equation is nearly in quadratic form.

Rewrite 9^(2x) as (9^x)^2

We get this equivalent equation (9^x)^2 - 2*(9^x) - 3 = 0

From here, let's make w = 9^x. Replace every copy of '9^x' with 'w' and we end up with this new simpler equation: w^2 - 2w - 3 = 0

From here we can use the quadratic formula or factor. I'll factor.

w^2 - 2w - 3 = 0

(w - 3)(w + 1) = 0

w-3 = 0 or w+1 = 0

w = 3 or w = -1

---------------------

Now we use these values of w to find x

If w = 3, then,

w = 9^x

3 = 9^x

log(3) = log(9^x)

log(3) = x*log(9)

x = log(3)/log(9)

x = log(3)/log(3^2)

x = log(3)/(2*log(3))

x = 1/2

At the last step, we have the log(3) terms cancel.

Repeat for w = -1

w = 9^x

-1 = 9^x

log(-1) = log(9^x)

We run into a problem. The log of any negative number is not a real number output. In other words, 9^x is never negative. Raising any positive number to a real number output leads the result to be positive. Take a look at the graph of y = 9^x to confirm this.

In short, w = -1 is extraneous so it doesn't lead to any x value solution.

So only w = 3 is useful.

Ultimately, the only solution is x = 1/2.

3 0
3 years ago
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