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kompoz [17]
3 years ago
11

What are the reactants in the following equation: hcl(aq) nahco₃(aq)→ co₂(g) h₂o(l) nacl(aq)

Chemistry
1 answer:
Triss [41]3 years ago
4 0
The reactants are all the formulas to the left of the arrow, which are:
hcI(aq) nahco3(aq)
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Within each energy level there are different sublevels that are created. Those electrons that have the lowest
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Which describes the difference between frogs and bacteria?
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6 0
3 years ago
Read 2 more answers
2. Determine the molarity of the NaOH solution in each trial. a. Trial 1 Molarity: b. Trial 2 Molarity: 3. Calculate the average
butalik [34]

Answer:

This question is incomplete

Explanation:

This question is incomplete but...

1) You can calculate the molarity of the NaOH for each trial by following the steps below.

The formula for Molarity (M) is

M = number of moles (n) ÷ volume (V)

where the unit of volume must be in Litres or dm³

The unit of molarity is mol/dm³ or mol/L or molar conc (M)

The final answer must have the unit of molarity

If the number of moles is not provided, look out for the mass of NaOH used and then calculate your number of moles (n) as

n = mass of NaOH used ÷ molar mass of NaOH

Where the atomic mass of sodium (Na) is 23, oxygen (O) is 16 and hydrogen (H) is 1. Hence, molar mass for NaOH is 23 + 16 + 1 = 40 g/mol

n = mass of NaOH used ÷ 40

2) Average Molarity will be (Trial 1 Molarity +Trial 2 Molarity) ÷ 2

Answer must be in mol/dm³ or mol/L or M

3) Label the volumentric flask containing the NaOH solution with the answer gotten from (2) above

3 0
3 years ago
Select the correct answer from each drop-down menu. consider the substances hydrogen (h2), fluorine (f2), and hydrogen fluoride
nasty-shy [4]

The boiling point of HF is higher than the boiling point of H_2, and it is higher than the boiling point of F_2.

<h3>What is the boiling point?</h3>

The boiling point is the temperature at which the pressure exerted by the surroundings upon a liquid is equalled by the pressure exerted by the vapour of the liquid.

F_2 has weak dispersion force attractions between its molecules, whereas liquid HF has strong ionic interactions between H^+ and F^- ions.

Only London Forces are formed - Therefore more energy is required to break the intermolecular forces in HF than in the other hydrogen halides and so HF has a higher boiling point.

H_2 and F_2 will only have intra-molecular attractions and there will be no hydrogen bonds present in them. As a result, their boiling point will be lower.

Hence, the boiling point of HF is higher than the boiling point of H_2, and it is higher than the boiling point of F_2.

Learn more about the boiling point:

brainly.com/question/25777663

#SPJ1

7 0
2 years ago
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