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astra-53 [7]
3 years ago
10

NEED HELP ASAP! I will post the observation now in different question​

Chemistry
1 answer:
ASHA 777 [7]3 years ago
8 0

Answer:

A. NO2 gas released, NO_{3}^{-} ion is present.

The residue is (ZnO) Zn oxide, Zn^{2+} ion is present.

The white salt is Zn(NO3)2.

B.     CO2 gas released, CO_{3}^{2-} ion present.

The residue ia (CuO ) Cu(||) oxide, Cu^{2+} ion present .

The green salt is CuCO3.

C.   CO2 gas released, CO_{3}^{2-} ion present.

The residue Pb(||) oxide, Pb^{2+} ion is present.

The white salt is PbCO3.

D. CO2 gas released, CO_{3}^{2-} ion present.

The residue is (ZnO) Zn oxide, Zn^{2+} ion is present.

The white salt is ZnCO3.

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Answer:

104.969 amu.

Explanation:

From the question given above, the following data were obtained:

Isotope A:

Mass of A = 107.977 amu

Abundance (A%) = 0.1620%

Isotope B:

Mass of B = 106.976 amu

Abundance (B%) = 1.568%

Isotope C:

Mass of C = 105.974 amu

Abundance (C%) = 47.14%

Isotope D:

Mass of D = 103.973 amu

Abundance (D%) = 51.13%

Average atomic mass =?

The average atomic mass of the element can be obtained as follow:

Average atomic mass = [(Mass of A × A%) /100] + [(Mass of B × B%) /100] + [(Mass of C × C%) /100] + [(Mass of D × D%) /100]

Average atomic mass = [(107.977 × 0.1620)/100] + [(106.976 × 1.568)/100] + [(105.974 × 47.14)/100] + [(103.973 × 51.13)/100]

= 0.175 + 1.677 + 49.956 + 53.161

= 104.969 amu

Therefore, the average atomic mass of the element is 104.969 amu.

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Answer:

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Hello!

To find the mass of helium, we need to multiply the total moles by the mass of helium. We are given 2.714 moles of helium, and the mass of helium is about 4.00 grams. Now, we multiply the two values together to get the grams.

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