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astra-53 [7]
3 years ago
10

NEED HELP ASAP! I will post the observation now in different question​

Chemistry
1 answer:
ASHA 777 [7]3 years ago
8 0

Answer:

A. NO2 gas released, NO_{3}^{-} ion is present.

The residue is (ZnO) Zn oxide, Zn^{2+} ion is present.

The white salt is Zn(NO3)2.

B.     CO2 gas released, CO_{3}^{2-} ion present.

The residue ia (CuO ) Cu(||) oxide, Cu^{2+} ion present .

The green salt is CuCO3.

C.   CO2 gas released, CO_{3}^{2-} ion present.

The residue Pb(||) oxide, Pb^{2+} ion is present.

The white salt is PbCO3.

D. CO2 gas released, CO_{3}^{2-} ion present.

The residue is (ZnO) Zn oxide, Zn^{2+} ion is present.

The white salt is ZnCO3.

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How many moles are there in 1.20 x 1025 particles of helium?
Anettt [7]

Answer:

You would get 19.969 moles.

Explanation:

You would get 19.969 moles.

3 0
2 years ago
What is the correct electron dot symbol for an alumminum atom in the ground state?
weqwewe [10]

Answer: Aluminum is in group IIIA of the periodic table therefore it has three valence electrons. The symbol for aluminum is Al which will be surrounded by three dots. 2.

Explanation:

7 0
3 years ago
Which of these statements about enzymes is true?
allochka39001 [22]
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and catalysts generally increase rate of reaction by lowering activation energy
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How many grams of a 22.9% sugar solution contain 68.5 g of sugar?
777dan777 [17]

    The grams  of 22.9 %   sugar  solution that contain 68.5  g  of   sugar  is 299.13 g  of  solution  

   <u><em>calculation</em></u>

 22.9%  means that  there are  22.9 g  of  sugar  in 100 g of solution.

   what about   68.5 g  of sugar

- <em>by cross    multiplication</em>

=[(68.5 g  sugar x 100  g  solution) /22.9  g sugar] =299.13 g  of solution

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5 0
3 years ago
The chemical shift of the CH3 protons in diethylether is δ = 1.16 and that of the CH2 protons is 3.36. What is the difference in
grandymaker [24]

Answer:

Where Blocal = local magnetic field between the two regions of the molecule

Blocal = (1-σ)B0

ΔBlocal = (1-σ1)B0 - (1-σ2)B0 = (σ2 - σ1)B0 = ΔσB0 ≈ ΔδB0 x 10∧-6

= (3.36-1.16) x 10∧-6 x B0 = 2.20 x 10∧-6B0

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(b) ΔBlocal = 2.20 x 10∧-6 x 16.5T = 36.3 μT

Explanation:

5 0
3 years ago
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