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Aleks04 [339]
4 years ago
12

What is -3/5 x -10/21?

Mathematics
1 answer:
sammy [17]4 years ago
7 0
The answer would be 2/7!
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in 1985, there were 285 cell phone subscribers in the small town of Centerville. the number of subscribers increased by 75% per
Vladimir79 [104]

Answer:

  43,872

Step-by-step explanation:

The growth of cell phone subscribers in Centerville can be modeled by an exponential function.

  y = ab^x . . . . . where a = initial value, b = growth factor

The growth rate is given as 75% per year, so x will have units of years. It will be zero for the year 1985. The growth factor is ...

  b = 1 + growth rate = 1 +0.75 = 1.75

Then the model is ...

  y = 285·1.75^x

__

For x = 1994 -1985 = 9, the number of subscribers is modeled as ...

  y = 285·1.75^9 ≈ 43,872

The model predicts 43,872 cell phone subscribers in 1994.

7 0
2 years ago
Figure PQRS is a parallelogram.
ASHA 777 [7]
Using the rule of angles in parallel lines, ∠Q and ∠R are supplementary to each other

∠Q+∠R = 180°
x+15+6x-10=180
7x+5=180
7x=180-5
7x=175
x=25

Size of ∠Q = 25+15 = 40°
Size of ∠R = 6(25) - 10 = 140°

∠Q also supplementary with ∠P, hence ∠P = 140°
∠P supplementary with ∠S, hence ∠S = 40°


7 0
3 years ago
Read 2 more answers
find the probability exactly 3 successes in 6 trials of a binomial experiment in which the probability of success if 50%. round
Dennis_Churaev [7]

Answer:

Hence, the probability of exactly 3 successes in 6 trials of a binomial experiment round to the nearest tenth of a percent is:

31.2%

Step-by-step explanation:

The probability of getting exactly k successes in n trials is given by the probability mass function:



{\displaystyle P(k;n,p)=P(X=k)={\binom {n}{k}}p^{k}(1-p)^{n-k}}

Where p denotes the probability of success.

We are given that  the probability of success if 50%.

i.e. p=\dfrac{1}{2}

also form the question we have:

k=3 and n=6.

Hence the probability of exactly 3 successes in 6 trials is:


{\displaystyle P(3;6,\dfrac{1}{2})=P(X=3)={\binom {6}{3}}(\dfrac{1}{2})^{3}(1-\dfrac{1}{2})^{6-3}}


{\displaystyle P(3;6,\dfrac{1}{2})=P(X=3)={\binom {6}{3}}(\dfrac{1}{2})^{3}(\dfrac{1}{2})^{3}}

{\displaystyle P(3;6,\dfrac{1}{2})=P(X=3)={\binom {6}{3}}(\dfrac{1}{2})^{6}

\binom {6}{3}=20

Hence,

{\displaystyle P(3;6,\dfrac{1}{2})=P(X=3)=20\times (\dfrac{1}{2})^6=\dfrac{5}{16}

In percentage the probability will be:

\dfrac{5}{16}\times 100=31.25\%=31.2\%



8 0
4 years ago
Please help! And get it right I hope!
andrezito [222]
1. 56
2. 10 
3. 16
4. 2
5. 12
7 0
3 years ago
The booster club recently bought new baseball equipment. They spent $18 per glove and $24 dollars per catching mask and spent a
hammer [34]

Answer:

given below

Step-by-step explanation:

let the number of gloves be y

then number of masks is y + 8

therefore a equation can be formed:

18(y) + 24(y + 8) = $612

18y+24y+192=612

42y=420

y=$10

each glove cost $10

therefore each masks cost $18

7 0
3 years ago
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