The average velocity of the object in moving from point-B to point-C is
(the straight-line distance and direction from point-B to point-C)
divided by
(the time the object takes to make the trip) .
Answer:
Initial velocity =
b) Height it reaches = 44.145 m
Explanation:
Using the first equation of motion we have

here
v is the final velocity
u is the initial velocity
a is the acceleration of the object
t is time
When the ball reaches it's highest point it's velocity will become 0 as it will travel no further
Also the acceleration in our case is acceleration due to gravity (
) as the ball moves in it's influence alone with '-' indicating downward direction
Thus applying the values we get

b)
By 3rd equation of motion we have

here s is the distance covered
Applying the value of u that we calculated we get

Answer:
0 m/s
Explanation:
Acceleration is a maximum at the lowest and highest positions. The velocity is 0 at these positions.
Answer:
The distance between the charges is 9.5 cm
(c) is correct option
Explanation:
Given that,
Charge 
Force F = 1 N
We need to calculate the distance between the charges
Using Coulomb's formula

Where, q = charge
r = distance
F = force
Put the value into the formula




Hence, The distance between the charges is 9.5 cm