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melamori03 [73]
3 years ago
5

What types of compounds are involved in solutions that are used to grow crystals? In your own words please

Physics
1 answer:
Alexandra [31]3 years ago
7 0

Answer:

This is a table of common chemicals that produce nice crystals. The color and shape of the crystals are included. Many of these chemicals are available in your home. Other chemicals in this list are readily available online and are safe enough for growing crystals at home or in a school. Recipes and specific instructions are available for hyperlinked chemicals.

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question how does the gravitational field gx at the surface of planet x compare with the gravitational field gy at the surface o
siniylev [52]

The  gravitational field gx at the surface of planet x  (M/m)(r/R)² times the gravitational field gy at the surface of planet y.

<h3>What is gravitational field?</h3>

A gravitational field, as defined by physics, is the influence a massive body has on the area surrounding it, exerting a force on another huge body. In other words, a gravitational field, which is measured in newtons per kilograms (N/kg), aids in the explanation of gravitational field.

Now, Let planet x has mass M and radius R:  then gravitational field at the surface of planet: gₓ = GM/R².

Let planet y has mass m and radius r:  then gravitational field at the surface of planet: g_y = Gm/r².

Hence, gₓ/g_y = (M/m)(r/R)².

So, the  gravitational field gx at the surface of planet x  (M/m)(r/R)² times the gravitational field gy at the surface of planet y.

Learn more about gravitational field here:

brainly.com/question/12324569

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8 0
2 years ago
In an RC series circuit, ℰ = 17.0 V, R = 1.60 M, and C = 1.80 µF.
LiRa [457]

Answer:

(a) τ=2.88 s, (b) q₀= 30.6μC and (c) t=1.434s            

Explanation:

A RC circuit is an resistor(R)-capacitor(C) electric circuit.    

(a) In a resistor-capacitor circuit, the time constant (τ) can be calculated by:    

\tau = RC          

<em>where R: is the resistence and C: the capacitance of the capacitor</em>

\tau = (1.60\cdot 10^{6} \cdot 1.80\cdot 10^{-6} = 2.88 s  

 

(b) The maximum charge (q₀) is giving by:    

q_{0} = \epsilon \cdot C  

<em>where ε: is the voltage across the capacitor</em>

q_{0} = 17.0 V \cdot 1.80 \cdot 10^{-6} F = 3.06 \cdot 10^{-5} C = 30.6 \mu C                  

(c) The time (t) that take the charge (q) to build up to 12 μC can be calculated from the next equation:  

q = q_{0}(1 - e(\frac{-t}{RC}))  

t = RC Ln( \frac{q_0}{q_0 - q}) = \tau Ln( \frac{q_0}{q_0 - q})

t = 2.88 \cdot Ln (\frac{30.6 \cdot 10^{-6}}{(30.6 \cdot 10^{-6} - 12.0 \cdot 10^{-6}})

t = 1. 434 s  

Have a nice day!

5 0
3 years ago
Why is copper a good conductor?
IgorLugansk [536]
Copper conducts electricity
4 0
3 years ago
Read 2 more answers
when the armature of an ac generatr rotates at 15.0 rad/s, the amplitude of the induced emf is 27.0 V. What is the amplitude of
nata0808 [166]

To solve this problem we will apply the concepts related to the electric field. This is defined as the product between the angular frequency, the number of turns of the body (solenoid in this case) the magnetic field and the sine of the angular frequency and time. Mathematically this can be described as

E = \omega NBA |sin \omega t|

Here,

\omega = Angular frequency

N = Number of turns

B = Magnetic field

The emf has its maximum value when sin \omega t = \pm 1

Thus the amplitude of the emf is

E = \omega NBA

When number of turns of armature, area and applied magnetic field remains constant, induced emf is proportional to angular speed.

E \propto \omega

Further it can be written as follows,

\frac{E_1}{E_2} \propto \frac{\omega_1}{\omega_2}

E_2 = \frac{\omega_2}{\omega_1}E_1

E_2 = \frac{10rad/s}{15rad/s}(27.0V)

E_2 = 18V

Therefore the maximum amplitude of induced emf when armature rotates at 10.0rad/s is 18V

5 0
3 years ago
Tera performed multiple experiments to determine the best growing conditions for Azaleas. In one experiment, she tested the effe
Ira Lisetskai [31]
The answer should be D. Ur right
8 0
3 years ago
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