Answer:
Explanation:
Mass of turn table, M = 35 kg
Radius of turn table, R = 2.2 m
initial angular velocity, ω = 11 rad/s
mass of clay, m = 17 kg
distance of clay from centre of table, r = 1.5 m
Let the final angular velocity is ω'.
By the use of conservation of angular momentum
I x ω = I' x ω'
where, I is the moment of inertia of the turn table = 0.5 MR²
I = 0.5 x 35 x 2.2 x 2.2 = 84.7 kg m²
I' is the moment of inertia of the table and the clay lump.
I' = I + mr² = 84.7 + 17 x 1.5 x 1.5 = 122.95 kg m²
Now
84.7 x 11 = 122.95 x ω'
ω' = 7.78 rad/s