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3 years ago

Questions:(a) Why should the amplitude of oscillation be small on a pendulum experiment

1 answer:

5 0

The formula for the pendulum experiment is based on the assumption that the amplitude is small so that the angle is approximately equal to the Sine of the angle.

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A 1.8-kg object is attached to a spring and placed on frictionless, horizontal surface. A force of 40 N stretches a spring 20 cm

Sergio [31]

Answer:

a) k = 200 N/m

b) E = 4 J

c) Δx = 6.3 cm

Explanation:

In order to find force constant of the spring, k, we can use the the Hooke's Law, which reads as follows:

$F = - k * \Delta x (1)$

where F = 40 N and Δx =- 0.2 m (since the force opposes to the displacement from the equilibrium position, we say that it's a restoring force).
Solving for k:

$k =- \frac{F}{\Delta x} =-\frac{40 N}{-0.2m} = 200 N/m (2)$

Assuming no friction present, total mechanical energy mus keep constant.
When the spring is stretched, all the energy is elastic potential, and can be expressed as follows:

$U = \frac{1}{2}* k* (\Delta x)^{2} (3)$

Replacing k and Δx by their values, we get:

$U = \frac{1}{2}* k* (\Delta x)^{2} = \frac{1}{2}* 200 N/m* (0.2m)^{2} = 4 J (4)$

When the object is oscillating, at any time, its energy will be part elastic potential, and part kinetic energy.
We know that due to the conservation of energy, this sum will be equal to the total energy that we found in b).
So, we can write the following expression:

$\frac{1}{2}* k* \Delta x_{1} ^{2} + \frac{1}{2} * m* v^{2} = \frac{1}{2}*k*\Delta x^{2} (5)$

Replacing the right side of (5) with (4), k, m, and v by the givens, and simplifying, we can solve for Δx₁, as follows:

$\frac{1}{2}* 200N/m* \Delta x_{1} ^{2} + \frac{1}{2} * 1.8kg* (-2.0m/s)^{2} = 4J (6)$

⇒ $\frac{1}{2}* 200N/m* \Delta x_{1} ^{2} = 4J - 3.6 J = 0.4 J (7)$

⇒ $\Delta x_{1} = \sqrt{\frac{0.8J}{200N/m} } = 6.3 cm (8)$

6 0

3 years ago

Many of water's emergent properties, such as its cohesion, its high specific heat, and its high heat of vaporization, result fro

Bingel [31]

Answer:

Option 5.

Explanation:

Many of the properties of water like high specific heat, cohesion, high vaporization heat, etc can be contributed to the polar nature of water molecule.

Water being a polar molecule as it contains positively charged hydrogen and an electro-negative oxygen which results in uneven or non uniformity in sharing of electrons which leads to dipole formation and hence polarization of the molecule due to which it attracts its neighboring molecules.

This polar nature imparts the properties like cohesion, surface tension , adhesion, etc due to the presence of hydrogen bonds in water molecule.

3 0

3 years ago

PLEASE HELP ASAPPPP! I ONLY HAVE 10 MINUTES!

alexgriva [62]

Answer:

4 gamma closest thing to this V

Explanation:

Technetium. Tc is a very versatile radioisotope, and is the most commonly used radioisotope tracer in medicine.

6 0

3 years ago

Cat walks 100 m East, then turns around and walks 25 m west. What is the cats displacement?

kvasek [131]

Answer:

Explanation:

If a cat walk 100m East, this means that it is walking in the positive x direction, the distance will therefore be +100m

If it turns around and walks 25 m west, the direction of movement is in the negative x direction i.e -25m

Taking the sum;

Displacement = +100m - 25m

Displacement of the cat = 75m

hence the cats displacement is 75m

8 0

3 years ago

A wooden block of mass m = 9 kg starts from rest on an inclined plane sloped at an angle θ from the horizontal. The block is ori

vredina [299]

Answer:

f = 0.283

Explanation:

With the given values x=5m and t=2s, the acceleration a of the block must be:

(1) $a=\frac{2x}{t^2}$

The sum of all forces in the inclined plane must be:

(2) $F=ma=sin(\theta) F_{gravity}-F_{friction}=sin(\theta) mg - f cos(\theta) mg$

Solving equation2 for the acceleration a:

(3) $a=sin(\theta) g - f cos(\theta) g$

Using equations 1 and 3 to solve for f:

$\frac{2x}{t^2}=sin(\theta) g - f cos(\theta) g\\f=tan(\theta)-\frac{2x}{t^2cos(\theta)g}$

4 0

3 years ago

Questions:(a) Why should the amplitude of oscillation be small on a pendulum experiment​

Questions:(a) Why should the amplitude of oscillation be small on a pendulum experiment