Question

PLEASE HELP!!! NEED TO PASS THIS TO THE FIRST SEMESTER!

Answer 1

Answer:

Reaction 1 is balanced but 2 is not balanced , the balance equation are :

1. $CH_{3}COOH(aq) + NaHCO_{3}(aq)\rightarrow CO_{2}(g) + H_{2}O(l) + CH_{3}COONa(aq)$

2.$CaCl_{2}(aq) + 2NaHCO_{3}(aq)\rightarrow CaCO_{3}(aq) + H_{2}O(l) + 2NaCl(aq) + H_{2}O(aq)$

Explanation:

Balanced Equations : These are the equation which follows the law of conservation of mass .

The total number of atoms present in reactant is equal to total number of atoms present in product.

1. $CH_{3}COOH(aq) + NaHCO_{3}(aq)\rightarrow CO_{2}(g) + H_{2}O(l) + CH_{3}COONa(aq)$

This is acid - base type reaction where

$CH_{3}COOH(aq)$ act as Acid

$NaHCO_{3}(aq)$ act as weak base

Reactant :$CH_{3}COOH(aq)$ ,$NaHCO_{3}$

Number of atoms of :

C = 2 ($CH_{3}COOH(aq)$) + 1 ($NaHCO_{3}$)

   = 2 + 1

   = 3

H  = 4($CH_{3}COOH(aq)$) + 1 ($NaHCO_{3}$)

     = 4 + 1

       5

O = 2($CH_{3}COOH(aq)$) + 3 ($NaHCO_{3}$)

    = 5

Na = 1 ($NaHCO_{3}$)

     = 1

Product :  $CO_{2}(g)$,$H_{2}O(l)$ , $CH_{3}COONa(aq)$

Number of atoms :

C = 1($CO_{2}(g)$) + 2($CH_{3}COONa(aq)$)

   = 1 + 2

   = 3

H = 2($H_{2}O(l)$) + 3($CH_{3}COONa(aq)$)

   = 2 + 3

   = 5

O = 1($H_{2}O(l)$) + 2($CH_{3}COONa(aq)$)

        +2($CO_{2}(g)$

    = 1 + 2 + 2

    = 5

Na = 1($CH_{3}COONa(aq)$

     = 1

Number of Na =1 , C = 3 , H= 5 and O =5 in both reactant and product , so it is a balanced reaction

2.$CaCl_{2}(aq) + 2NaHCO_{3}(aq)\rightarrow CaCO_{3}(aq) + H_{2}O(l) + 2NaCl(aq) + CO_{2}(g)$

This is double displacement reaction .

Check the balancing in both reactant and products should be :

Na = 2

H = 2

Ca = 1

C = 2

O = 6

Cl = 2