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4 years ago

Which statement describes the relationship between

Chemistry

1 answer:

timofeeve [1]4 years ago

3 0

Answer:

I'd have to see the diagram to figure this out. im sorry

Explanation:

if you have another question, i'll help

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An ideal gas in a cylindrical container of radius r and height h is kept at constant pressure p. The bottom of the container is

Juli2301 [7.4K]

Answer:

$m =\frac{p*(pi)*r^{2}*h*mw}{R*\frac{T_{1} + T_{O}}{2}}$

Explanation:

The gas ideal law is

PV= nRT (equation 1)

Where:

P = pressure

R = gas constant

T = temperature

n= moles of substance

V = volume

Working with equation 1 we can get

$n =\frac{PV}{RT}$

The number of moles is mass (m) / molecular weight (mw). Replacing this value in the equation we get.

$\frac{m}{mw} =\frac{PV}{RT}$ or

$m =\frac{P*V*mw}{R*T}$ (equation 2)

The cylindrical container has a constant pressure p

The volume is the volume of a cylinder this is

$V =(pi)*r^{2}*h$

Where:

r = radius

h = height

(pi) = number pi (3.1415)

This cylinder has a radius, r and height, h so the volume is $V =(pi)*r^{2}*h$

Since the temperatures has linear distribution, we can say that the temperature in the cylinder is the average between the temperature in the top and in the bottom of the cylinder. This is:

$T =\frac{T_{1} + T_{O}}{2}$

Replacing these values in the equation 2 we get:

$m =\frac{P*V*mw}{R*T}$ (equation 2)

$m =\frac{p*(pi)*r^{2}*h*mw}{R*\frac{T_{1} + T_{O}}{2}}$

8 0

3 years ago

Which of the following sets of empirícal formula, molar mass, and molecular formula is correct?

skad [1K]

Answer:

The option C is correct.
CH4N, 90g, C3H12N3.

Explanation:

Option C:

The molecular formula is C3H12N3.

If we take ratio 3:12:3 that will be equal to 1:4:1 so its empirical formula will be CH4N.
The molar mass of molecular formula = (12×3) + (1×12) +( 14×3) = 98 g

Option A :

In option A , molecular and empirical formula are both correct but molar mass is not valid. It should be 169 acc. to molecular formula.

Option B:

In option B, molecular formual is not valid.
It should be as C6H16O2

4 0

3 years ago

Draw the structure of the bromohydrin formed when (Z)-3-hexene reacts with Br2/H2O. Use the wedge/hash bond tools to indicate st

Ipatiy [6.2K]

Answer:

(3R,4R)-4-bromohexan-3-ol

Explanation:

In this case, we have reaction called halohydrin formation. This is a markovnikov reaction with anti configuration. Therefore the halogen in this case "Br" and the "OH" must have different configurations. Additionally, in this molecule both carbons have the same substitution, so the "OH" can go in any carbon.

Finally, in the product we will have chiral carbons, so we have to find the absolute configuration for each carbon. On carbon 3 we will have an "R" configuration on carbon 4 we will have also an "R" configuration. (See figure 1)

I hope it helps!

5 0

3 years ago

The two boron atoms listed in the table are isotopes of the boron. The two carbon atoms and the two oxygen atoms are also called

Ivan

Answer:

A type of an atom which has a different number of neutrons but the same atomic number, therefore making it the same element. This atom would still have the same properties as well. (Ex: Vanadium-51 is an isotope of Vanadium that has 51 neutrons but still has 23 protons, as its atomic number is 23.)

3 0

2 years ago

How many significant figures does .150, 20.20, and 25.00 have?

viva [34]

.150 = 3
20.20 = 4
25.00 = 4
If a 0 does not have a number or a period after it, it is not significant.
If the 0 is behind the decimal point, it is always significant.

6 0

3 years ago